All categories

2 years ago

Choose the reaction that represents the combustion of C6H12O2.

Chemistry

2 answers:

Leona [35]2 years ago

4 0

Answer:

The answer to your question is: letter D

Explanation:

In a combustion reaction, the reactants are always a molecule with Carbon that reacts with oxygen and the products are carbon dioxide and water.

According to the explanation, the only possible solution is:

a) C₆H₁₂O₂(l) ⇒ 6 C(s) + 6 H₂(g) + O₂(g)

b) Mg(s) + C₆H₁₂O₂(l) ⇒ MgC₆H₁₂O₂(aq)

c) 6 C(s) + 6 H₂(g) + O₂(g) ⇒ C₆H₁₂O₂(l)

d) C₆H₁₂O₂(l) + 8 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(g)

e) None of the above represent the combustion of C₆H₁₂O₂.

Gnom [1K]2 years ago

4 0

Answer : The balanced combustion reaction of $C_6H_{12}O_2$ will be:

$C_6H_{12}O_2(l)+8O_2(g)\rightarrow 6CO_2(g)+6H_2O(g)$

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

Combustion reaction : A chemical reaction in which a hydrocarbon react with the oxygen to give product as carbon dioxide and water.

The balanced combustion reaction of $C_6H_{12}O_2$ will be:

$C_6H_{12}O_2(l)+8O_2(g)\rightarrow 6CO_2(g)+6H_2O(g)$

You might be interested in

What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig

Mashutka [201]

Answer:

$P_H =2.86$

$c=1.4\times 10^{-4}$

Explanation:

first write the equilibrium equaion ,

$C_3H_6O_3$ ⇄ $C_3H_5O_3^{-} +H^{+}$

assuming degree of dissociation $\alpha$ =1/10;

and initial concentraion of $C_3H_6O_3$ =c;

At equlibrium ;

concentration of $C_3H_6O_3 = c-c\alpha$

$[C_3H_5O_3^{-} ]= c\alpha$

$[H^{+}] = c\alpha$

$K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}$

$\alpha$ is very small so $1-\alpha$ can be neglected

and equation is;

$K_a = {c\alpha \times \alpha}$

$[H^{+}] = c\alpha$ = $\frac{K_a}{\alpha}$

$P_H =- log[H^{+} ]$

$P_H =-logK_a + log\alpha$

$K_a =1.38\times10^{-4}$

$\alpha = \frac{1}{10}$

$P_H= 3.86-1$

$P_H =2.86$

composiion ;

$c=\frac{1}{\alpha} \times [H^{+}]$

$[H^{+}] =antilog(-P_H)$

$[H^{+} ] =0.0014$

$c=0.0014\times \frac{1}{10}$

$c=1.4\times 10^{-4}$

6 0

3 years ago

Using wolfram alpha or some other reference, determine which of these elements would be liquid at 525 k (assume samples are prot

romanna [79]

The choices for this problem are bismuth, Bi; platinum, Pt; selenium, Se; calcium, Ca and copper, Cu. I think the correct answer would be selenium. The melting point of bismuth is at a temperature of 544.4 Kelvin. At a temperature of 525 K, it would exist as solid. Platinum melts at 2041.1 K. At 525 K, platinum would be in solid form. Selenium has a melting point at 494 K so that at a temperature of 525 K, it would exist in its liquid state. Calcium has a melting point of 1112 K so it would exist as solid at 525 K. Copper has a melting point at 1358 K, so it would still exist as solid at a temperature of 525 K. Therefore, the answer would only be selenium.

3 0

3 years ago

if you are told to get 100 mL of stock solution to use to prepare smaller size sample for an experiment, which piece of glasswar

fgiga [73]

Answer:

A beaker

Step-by-step explanation:

Specifically, I would use a 250 mL graduated beaker.

A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.

You don't need precisely 100 mL solution.

If the beaker is graduated, you can easily measure 100 mL of the stock solution.

Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).

6 0

2 years ago

Calculate the kinetic energy of a 8.8 x 10^13 kg comet moving at a speed of 33.0 km/s. Round your answer to 2 significant digits

g100num [7]

Answer:

$KE=4.79\times 10^{22}\ J$

Explanation:

Given that

Mass ,m= 8.8 x 10¹³

Speed ,v= 33 km/s

We know that 1 km= 1000 m

v= 33 x 10³ m/s

As we know that kinetic energy given as

$KE=\dfrac{1}{2}mv^2$

Now by putting the values in the above equation

$KE=\dfrac{1}{2}\times 8.8\times 10^{13}\times 33000^2$

$KE=4.7916\times 10^{22}\ J$

Therefore we can say that the kinetic energy will be

$KE=4.79\times 10^{22}\ J$

6 0

3 years ago

You have just discovered a new organism.it is a single cell and has a cell wall but no nucleus. What kind of organism is it? Exp

jolli1 [7]

If it is a single cell then it is unicellular. it is an animal cell if it ha no cell wall and cells without nucleus are prokaryotes so it could be a Monera like bacteria.

8 0

3 years ago