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Amanda [17]
2 years ago
11

Descoberto em 1996 por pesquisadores alemães o novo elemento químico de numero 112 poderá ser batizado de copernicium em homenag

em ao cientista e astronomo Nicolau Copérnico segundo os cientistas o elemento é aproximadamente é 277 vezes mais pesado que o hidrogênio, o que torna o elemento mais pesado da tabela periódica ocupando a posição relativaa ao 7°periodo do grupo 12. A tabela periódica, uma das realizaações mais notáveis da quimica, foi desenvolivda exclusivamente a partir das propriedades fisícas e químmicas dos elementos e, por isso, o conhecimento da posição ocupada por um elemento químico permite que se façam algumas previsões quanto às suas propriedades.
considerando a localização dos átomos dos elementos químicos x, y e z na tabela periódica é incorreto afirmar que

x = 3° período do grupo 1 (I A)
y = 2° período do Grupo 14 (IV A)
z = 2° período do grupo 16 (VI A)

Chemistry
1 answer:
elena-14-01-66 [18.8K]2 years ago
7 0

Answer:

Loading...

Explanation:

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When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 16.8g of carbon were burned in the presence of
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61.6 grams of carbon dioxide was produced
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2 years ago
How many grams of the excess reactant remain assuming the reaction goes to completion and that you start with 15.5g of na2s and
tangare [24]
The reaction between Na2S and CuSO4 will give us the balanced chemical reaction of,
                                     Na2S + CUSO4 --> Na2SO4 + CuS
This means that for every 78g of Na2S, there needs to be 159.6 g of CuSO4. The ratio is equal to 0.4887 of Na2S: 1 of CuSO4. Thus, for every 12.1g of CuSO4, we need only 5.91 g of Na2S. Thus, there is an excess of 9.58 g of Na2S. The answer is letter C. 
8 0
3 years ago
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What volume of 0.500 M HNO3(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?
asambeis [7]
KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol HNO3= 1 mol KOH (keep in mind this because it will be used later).

We also know that 0.100 M KOH aqueous solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the definition of molarity).

First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/ 1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.

Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.

The final answer is </span>(2) 20.0 mL.<span>

Also, this problem can also be done by using dimensional analysis. 

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6 0
3 years ago
According to the following reaction, how many grams of hydrogen
Mila [183]

Answer:

7.03 g

Explanation:

Step 1: Write the balanced synthesis reaction

N₂(g) + 3 H₂(g) ⇒ 2 NH₃(g)

Step 2: Calculate the moles corresponding to 32.5 g of N₂

The molar mass of N₂ is 28.01 g/mol.

32.5 g × 1 mol/28.01 g = 1.16 mol

Step 3: Calculate the number of moles of H₂ needed to react with 1.16 moles of N₂

The molar ratio of N₂ to H₂ is 1:3. The moles of H₂ needed are 3/1 × 1.16 mol = 3.48 mol.

Step 4: Calculate the mass corresponding to 3.48 moles of H₂

The molar mass of H₂ is 2.02 g/mol.

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8 0
3 years ago
Individual measurements introduce errors that may be large or small depending on the quality of the tools and processes used. Sc
kirill [66]

Answer:

B. accepted value x 0.1

Explanation:

in the equation provided

Percentage Error=\frac{Error}{AcceptedValue} X100

Maximum allowed value of percentage error = 10%

put this value in the equation in stead of percentage error we get,

10 = \frac{error}{AcceptedValue} X100\\ \frac{10}{100} =\frac{error}{AcceptedValue}\\.1=\frac{error}{AcceptedValue}\\error = .1 X Accepted Value

so maximum error = .1 x accepted value

10 % percentage error means the experimental value has 10 % error compared to accepted value.so error will be 10 % of the accepted value

or .1 times of accepted value

8 0
3 years ago
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