All BUT one factor contributes to natural selection. That factor is

2 answers:

7 0

<span>the one that is not a factor that contribute to natural selection is : Population stability population refer to the capability of a community to maintain its total amount of organisms within a specific period of time. This has nothing to do with natural selection, which basically a nature's way to reduce the number of organism to findout which organisms are more adaptive</span>

laiz [17]3 years ago

7 0

Answer:B

Explanation:

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A car driving at 105 km/h. what is the speed in mi/min?<br> (1 mi = 1.61 km)

DedPeter [7]

Answer:

1.087 mi/min

Explanation:

Given data:

Speed of car in Km/h = 105

Speed of car in miles/min = ?

Solution:

It is given that one miles = 1.61 Km

while it is known that one hour = 60 minutes

Thus in order to convert the km/h into mi/min we will divide the given value by 96.561.

105 / 96.561

1.087 mi/min

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Inessa05 [86]

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Explanation:

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3 years ago

Two billiard balls having masses of 0.2 kg and 0.15kg approach each other. The first ball having a velocity of 2m/s hit the seco

Gekata [30.6K]

Answer: The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

Explanation:

Given: $m_{1}$ = 0.2 kg, $m_{2}$ = 0.15 kg

$v_{1}$ = 2 m/s, $v_{2}$ = 0 m/s, $v'_{1}$ = ?, $v'_{2}$ = 1.5 m/s

Formula used is as follows.

$m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}$

where,

v = velocity before collision

v' = velocity after collision

Substitute the values into above formula as follows.

$m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}\\0.2 kg \times 2 m/s + 0.15 kg \times 0 m/s = 0.2 kg \times v'_{1} + 0.15 kg \times 1.5 m/s\\0.4 kg m/s + 0 = 0.2v'_{1} + 0.225 kg m/s\\0.2v'_{1} kg = 0.175 kg m/s\\v'_{1} = \frac{0.175 kg m/s}{0.2 kg}\\= 0.875 m/s$