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Pie
3 years ago
13

All BUT one factor contributes to natural selection. That factor is

Chemistry
2 answers:
Juli2301 [7.4K]3 years ago
7 0
<span>the one that is not a factor that contribute to natural selection is : Population stability population refer to the capability of a community to maintain its total amount of organisms within a specific period of time. This has nothing to do with natural selection, which basically a nature's way to reduce the number of organism to findout which organisms are more adaptive</span>
laiz [17]3 years ago
7 0

Answer:B

Explanation:

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Diamond is a natural form of pure carbon. What number of atoms of carbon are in a 1.00-carat diamond (1.00 carat = 0.200 g)?
slega [8]

Answer:

1.004×10²²

Explanation:

The molar mass of carbon is 12 g/mol

which means that:

<u>1 mole of carbon atoms has a mass of 12 grams.</u>

Since, diamond is a allotrope of carbon.

Mass of  1.00-carat diamond in grams is:

1.00 carat = 0.200 g

<u> Since, 1 mole of C contains 6.022×10²³ atoms of C</u>

So,  

12 grams contains 6.022×10²³ atoms of C

1 gram contains 6.022×10²³/ 12 atoms of C

0.200 gram contains (6.022×10²³/ 12)×0.200 atoms of C

Thus,

<u>1 carat diamond contains 1.004×10²² atoms of C.</u>

8 0
3 years ago
Calculate the density of a solid in g/cm3 if it weighs 38.3 kg and has a volume of 0.00463 m3.
RideAnS [48]

Answer: D=8.27 g/cm³

Explanation:

Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.

D=\frac{38.3kg}{0.00463m^3} *\frac{(1m)^3}{(100cm)^3} *\frac{1000g}{1kg}

With this equation, the m³ and kg cancel out, and we are left with g/cm³.

D=8.27 g/cm³

3 0
3 years ago
The correct electron configuration of the O2-ion is
Mnenie [13.5K]
I think it’s A sorry if i’m wrong
6 0
3 years ago
How many moles of chlorine are in 100g of chlorine
cricket20 [7]
No. of moles = mass / molar mass
= 100/35.5
5 0
3 years ago
If the bucket were left outside on a hot day but brought inside before any evaporation occurred, how would the mass be affected?
dangina [55]
It wouldnt because nothing changed
5 0
3 years ago
Read 2 more answers
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