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ollegr [7]
2 years ago
10

3. A teacher prepared 0.125 M sodium chloride stock solution. What volume of the stock solution is

Chemistry
1 answer:
8090 [49]2 years ago
5 0

Answer:

B. po ang sagot

Explanation:

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Not sure....HELP!!!!!!!
Murrr4er [49]
Correct. the answer is c
4 0
3 years ago
Give the spectator ions for the reaction that occurs when aqueous solutions of H 2SO 4 and KOH are mixed.
Sever21 [200]

Answer:

The spectator ions is: K^+   and  SO^{2-}_4

Explanation:

The equation of reaction between  H₂ SO₄ and KOH is:

H_2SO_{4(aq)} + 2KOH _{aq} \to K_2SO_{4(aq)} +2H_2O _{(l)}

Rewriting this equation as ionic;

[2H^{+} + SO^{2-}_4 + 2K^+ +2OH^- \to 2K^+  SO_4^{2-} + 2H_2O ]

Spectators ions are ions present on both sides of the ionic equation by the same quantity but do not take part in the net reaction.

5 0
3 years ago
Calculate the mass in grams, in 2.28 mol of H2SO4. Please show your work to receive credit.
solmaris [256]

Answer:

98g

Explanation:

h=1*2=2

s=32

0=16*4=64

64+32+2=98

4 0
3 years ago
Explain why most metals are malleable and ductile but ionic crystals are not
Dima020 [189]
Throughout the metallic structure allowing the atoms to slide past each other. This sliding is why metals are ductile and malleable. Ioniccompound must break bonds to slide past one another, which causes the ionic material to split and crack.
7 0
4 years ago
Read 2 more answers
How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC?
vodomira [7]

Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J

Explanation:

1) Data:

Water ⇒ C = 1 cal/g°C

m = 65.8 g

Ti = 31.5°C

Tf = 36.9°C

Heat, Q = ?

2) Formula:

Q = mCΔT

3) Calculations:

Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal

4) You can convert from calories to Joules using the conversion factor:

1 cal = 4.18 J

⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J

3 0
3 years ago
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