3 years ago

6) What happens to the diameter of the field of view as the magnification increases?

1 answer:

4 0

Answer:

There is an inverse relationship between the total magnification and the diameter of the field of view – i.e., as magnifications increases the diameter of the field decreases in proportion, so the diameter of field of view at different magnification can be calculated mathematically, using the formula.

Step-by-step explanation:

You might be interested in

Simplify the expression. Write your answer as a power. <img src="https://tex.z-dn.net/?f=%285%5E%7B4%7D%20%29%5E%7B3%7D" id=

Charra [1.4K]

Answer:

$5^{12}$

Step-by-step explanation:

Lets say there's a number 'x' and there's an expression $(x^a)^b$ where 'a' & 'b' are also numbers , the simplified form of the expression is $x^{a \times b}$ .

So ,

$(5^4)^3 = 5^{4 \times 3} = 5^{12}$

6 0

2 years ago

If you pull a random card from a deck and keep it, and then pull another card, are the two events independent or dependent ?

serious [3.7K]

The events are dependent

5 0

3 years ago

Twice the difference of a number and 2 is 9

likoan [24]

2(n-2)=9
That's the answer. U just set it up as it is written

6 0

3 years ago

Find the value of x.Triangle with midsegment drawn. The midsegment measures 45 units and the side parallel to the midsegment mea

Charra [1.4K]

According to the Triangle Midsegment Thereom, if the midsegment of a triangle is parallel to a side of the triangle, then the midsegment is half the length of side it is parallel to, therefore...
45=(7x+13)/2
And after that, you continue to solve the problem using Algebra
90=7x+13
77=7x
11=x
I hope this answer was helpful! :)

6 0

3 years ago

Rope on a boat. A rope passing through a capstan on a dock is attached to a boat offshore. The rope is pulled in at a constant r

katrin2010 [14]

If it is being pulled in at a constant rate of 3ft/sec, then it is travelling 3 ft/sec is it not? knot? lol

8 0

3 years ago