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snow_lady [41]
2 years ago
6

Which equation represents the line shown on the coordinate grid below

Mathematics
1 answer:
Vladimir [108]2 years ago
8 0

Answer:

D>  y = (2/5)x - 2

Step-by-step explanation:

See attached

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on the last 5 quizzes, marco has earned a total of 21 out of 25 possible points. if he has a perfect score on the next several q
nevsk [136]

Using the mean concept, it is found that we will need 15 more points to bring up his average up to 90%.

The mean of a data-set is the <u>sum of all observations divided by the number of observations</u>.

In this problem:

  • In the first 5 observations, total of 21 out of 25 points, hence the mean for these observations is \frac{21}{25} = 0.84.
  • In the next n observations, mean of 1.

Hence, the mean is:

M = \frac{0.84(5) + n}{5 + n} = \frac{4.2 + n}{5 + n}

We want the mean to be of 0.9, thus:

M = 0.9

\frac{4.2 + n}{5 + n} = 0.9

4.2 + n = 0.9n + 4.5

0.1n = 0.3

n = \frac{0.3}{0.1}

n = 3

3 more testes are need, each worth 5 points, hence, 15 more points are needed to bring up his average up to 90%.

A similar problem is given at brainly.com/question/25323941

6 0
3 years ago
Suppose that you earned a​ bachelor's degree and now​ you're teaching high school. The school district offers teachers the oppor
stepan [7]

Answer:

Step-by-step explanation:

Answer:

a. The amount that is saved at the expiration of the 5 year period is $22,769.20¢

b. The amount of interest is $2,769.20¢

Step-by-step explanation:

Since the amount that is deposited every year for a period of five years is $4,000 and the rate of the interest is 6.5%. We can always calculate the amount that is saved at the expiration of the five years.

    We will first state the formula for calculating the future value of annuity:-

      Future value of annuity =

                      P[\frac{(1 + r)^{t}-1 }{r}]

   Where P is the amount deposited per year.

   r is the rate of interest

   t is the time or period

 

    and in this case, the actual value of P = $4,000

      rate of interest, r is 6.5% = 0.065

      time, t is 5 years.

   Substituting e, we have:

   Fv of annuity =

                          4,000[\frac{(1 + 0.065)^{5}-1 }{0.065 }]

   = 4,000 × [((1.065)^5)- 1/0.065]

 = 4,000 × [(1.37 - 1)/0.065]

 = 4,000 × (0.37/0.065)

 = 4,000 × 5.6923

 = $22,769.20¢

a. Therefore the amount that is saved at the end of the five (5) years is $22,769.20¢

b. To find the interest, we will calculate the amount of deposit made during the period of five years and subtract the sum from the current amount that is saved ($22,769.29¢).

  Since I deposited 4,000 every year for five years, the total amount of deposit I made at the period =

       4,000 × 5 = $20,000

  The amount of interest is then = $22,769.20¢ - $20,000 = $2,769.20¢

3 0
3 years ago
Solve for x. x + 7 -3 = 1<br><br><br> i need help
MA_775_DIABLO [31]
X+7-3=1 X+4=1 -4 -4 X=-3 Copy exactly how you see it
8 0
3 years ago
Halp me please i don't wanna fail...I wanna pass this test ;--; (MUST BE A EXPRESSION)
vaieri [72.5K]

Answer:

155+27n

Step-by-step explanation:

hope this helps

6 0
3 years ago
Read 2 more answers
An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an
igomit [66]

Answer:

Mean = 1.57

Variance=0.31

Step-by-step explanation:

To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

1) Both surgeries are successful (X=2).

P(e_1)=0.90*0.67=0.603

2) Left knee unsuccessful and right knee successful (X=1).

P(e_2)=(1-0.9)*0.67=0.1*0.67=0.067

3) Right knee unsuccessful and left knee successful (X=1).

P(e_3)=0.90*(1-0.67)=0.9*0.33=0.297

4) Both surgeries are unsuccessful (X=0).

P(e_4)=(1-0.90)*(1-0.67)=0.1*0.33=0.033

Then, the mean can be calculated as the expected value:

M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57

The variance can be calculated as:

V=\sum p_i(X_i-\bar{X})^2\\\\V=0.603(2-1.57)^2+(0.067+0.297)*(1-1.57)^2+0.033*(0-1.57)^2\\\\V=0.603*0.1849+0.364*0.3249+0.033*2.4649\\\\V=0.1115+0.1183+0.0813\\\\V=0.3111

3 0
3 years ago
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