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UkoKoshka [18]
2 years ago
9

Enrique can spend at most $2240 to renovate his home. One roll of wallpaper costs $32, and one can of paint costs $28. He needs

at least 30 rolls of wallpaper and at least 20 cans of paint. Identify the graph that shows all possible combinations of wallpaper and paint that he can buy. Also, identify two possible combinations.
Mathematics
1 answer:
umka2103 [35]2 years ago
6 0

The possible solution is having 30 rolls of wallpaper and 20 can of paints or 30 rolls of wallpaper with 46 can of paint.

<h3>Inequality</h3>

Inequality is the non equal comparison of two or more numbers and variables.

Let x represent the number of wallpapers and y represent the number of cans.

He needs at least 30 rolls of wallpaper and at least 20 cans of paint. Hence:

x ≥ 30   (1);

y ≥ 20    (2)

Also:

32x + 28y ≤ 2240    (3)

Plotting the 3 equations using geogebra online graphing tool, the possible solution is:

(30, 20), (30, 46)

The possible solution is having 30 rolls of wallpaper and 20 can of paints or 30 rolls of wallpaper with 46 can of paint.

Find out more on Inequality at: brainly.com/question/24372553

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Which is the graph of the system of equations?<br> x + 2y = 2<br> 4x - y = 4
Sladkaya [172]
Solve for x for x: x+2y=2
x+2y +-2y=2+-2y (add -2y on both sides.)
x=-2y+2
Substitute : -2y+2 for x in
4x-y=4:
4(-2y+2)-y=4
-9y+8=4 Simplify both sides of the equation.
-9y+8+-8=4+-8 Add -8 to both sides.
-9y=-4
-9/-9=-4-9 Divide both sides by -9
y=4/9
Substitute 4/9 for y in
x=-2y+2
x=-2(4/9)+2
x=10/9
y=4/9,x=10/9




4 0
3 years ago
Р
melisa1 [442]

Answer:

209 inches

Step-by-step explanation:

95% of 220 is 209 inches so therefor it would be 209 inches.

6 0
3 years ago
The formula for finding the number of bacteria present is given by P=P0(10)t where P is the final population, P0 is the initial
frozen [14]

Answer:

5.45 hours.

Step-by-step explanation:

The formula =

P = P0(10)t

In this circumstance, P0 = 275, P = 15,000 and t = ?

Applying the values into the formula:

P = P0(10)t

15,000 = 275 × (10) × t

15,000 = 2750t

t = 15,000/2750

t = 5.45 hours

3 0
2 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
2 years ago
Any help? Thanks in advance!
fgiga [73]

Answer:

c

Step-by-step explanation:

2^{4}=16

\sqrt[3]{16}

7 0
3 years ago
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