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vladimir1956 [14]
3 years ago
15

Jim needs to conduct his experiment at STP .Which condition must he use?

Chemistry
1 answer:
algol133 years ago
3 0

Answer:

273 K, 101.3 kPa

Explanation: I just did the quiz

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1. Based on this graph, how does metal A differ from metal B?
notka56 [123]

Answer:

B.Metal B has higher density than metal A

7 0
3 years ago
The lipid portion of a typical bilayer is about 30 Å thick. a) Calculate the minimum number of residues in an α-helix required t
Mrrafil [7]

Answer:

a) The minimum number of residues in alfa helix to span 30 Å, is 20 residues

b) The minimum number of residues in a Beta sheet to span 30 Å, is 8.6 residues.

c) Should be better if you show an image to do this question.

d) Look answer below.

Explanation:

a) Due to every 5,4 Å there are 3,6 residues. So doing the calculus give us 20 residues.

b)  That’s it because every 7 Å there are 2 residues

c) First of all, is important to know that the residues of a protein define the secondary structure due to intermolecular and intramolecular interactions. Taking in account that the membrane bilayer has a lipid interior α-helical domains which are hydrophobic principally are embedded in membranes by hydrophobic interactions with the lipid interior of the bilayer favored by Van der Waals interactions and probably also by ionic interactions with the polar head groups of the phospholipids.

3 0
4 years ago
The system co2(g) + h2(g) ⇀↽ h2o(g) + co(g) is at equilibrium at some temperature. at equilibrium a 4.00 l vessel contains 1.00
Marina CMI [18]

<u>Answer:</u> The moles of CO_2 added to the system is 7.13 moles

<u>Explanation:</u>

We are given:

Moles of CO_2 at equilibrium = 1.00 moles

Moles of H_2 at equilibrium = 1.00 moles

Moles of H_2O at equilibrium = 2.40 moles

Moles of CO at equilibrium = 2.40 moles

Volume of the container = 4.00 L

Concentration is written as:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}

The given chemical equation follows:

CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)

The expression of K_c for above equation follows:

K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}

Putting values in above equation, we get:

K_c=\frac{(\frac{2.40}{4.00})\times (\frac{2.40}{4.00})}{(\frac{1.00}{4.00})\times (\frac{1.00}{4.00})}\\\\K_c=5.76

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of CO = 0.791 mol/L

Volume of solution = 4.00 L

Putting values in above equation, we get:

0.791M=\frac{\text{Moles of CO}}{4.00L}\\\\\text{Moles of CO}=(0.791mol/\times 4.00L)=3.164mol

Extra moles of CO = (3.164 - 2.40) = 0.764 moles

Let the moles of CO_2 needed be 'x' moles.

Now, equilibrium gets re-established:

              CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)

Initial:       1.00      1.00              2.40       2.40

At eqllm:   (0.236+x)   0.236      3.164     3.164

Again, putting the values in the expression of K_c, we get:

5.76=\frac{(\frac{3.164}{4.00})\times (\frac{3.164}{4.00})}{(\frac{0.236+x}{4.00})\times (\frac{0.236}{4.00})}\\\\5.76=\frac{10.011}{0.056+0.236x}\\\\x=7.13

Hence, the moles of CO_2 added to the system is 7.13 moles

4 0
3 years ago
Which statement correctly describes a characteristic that a scientific measuring toll should have?
Gwar [14]

Answer:

Explanation:

To be accurate, it must be able to make measurements that are close to the actual value.

6 0
3 years ago
What is the value of the temp 15 degrees Celsius in degree kelvin
dybincka [34]
Just add 273 to it. u'll get 288 kelvin =)
8 0
3 years ago
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