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vladimir1956 [14]
3 years ago
15

Jim needs to conduct his experiment at STP .Which condition must he use?

Chemistry
1 answer:
algol133 years ago
3 0

Answer:

273 K, 101.3 kPa

Explanation: I just did the quiz

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A scientist compares two samples of white powder. one powder was present at the beginning of an experiment. the other powder was
NARA [144]

Answer. Chemical reaction had occurred and both the powders are different substances.

Explanation:

As density is an intensive property of the substance.Which means that  different substance have different densities.

Density = \frac{mass}{volume}

Density of powder 1, d_1=\frac{0.5g}{45cm^3}=0.11g/cm^3

Density of powder 2, d_2=\frac{1.3g}{65cm^3}=0.02g/cm^3

On comparing both the densities of the powders we can say that both the substances are different. So we can conclude that the chemical reaction had occurred.

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3 years ago
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Can u pls help me with this question ​
muminat

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it's mass

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just trust me it's just mass

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4 years ago
The reaction below was carried out in an acidic solution l-+10-3--->l2 Which statement is true about this equation? Although
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be cool

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Given 1.00 grams of each of the following radioisotopes, Ca-37, U-238, P-32 and Rn-222,which would have the least remaining orig
erica [24]
1) Ca-37, with a half-life of 181.1(10) ms.
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Hydrofluoric acid is used in the preparation of numerous pharmaceuticals (e.g., Prozac) and industrial materials (e.g., Teflon).
Natali [406]

Answer:

the equilibrium concentration of HF is 2.85 M

Option a) 2.85 M is the correct answer.

Explanation:

Given the data in the question;

     H₂         +      F₂      ⇄     2HF

I    1.69 M        1.69 M           0

C    -x                 -x               +2x

E    1.69-x         1.69-x          +2x

given that Kc = 115        

Kc = [ HF ]² / [H₂][F₂]

we substitute

115 = [ 2x ]² / [ 1.69-x  ][ 1.69-x ]

lets find the square root of both sides

10.7238 = 2x / [ 1.69-x  ]

10.7238[ 1.69-x  ] = 2x

18.123222 - 10.7238x = 2x

2x + 10.7238x = 18.123222

12.7238x = 18.123222

x = 18.123222 / 12.7238

x = 1.424356

Hence, equilibrium concentration of HF = 2x

that is;

HF = 2 × 1.424356

HF = 2.8487 ≈ 2.85 M

Therefore, the equilibrium concentration of HF is 2.85 M

Option a) 2.85 M is the correct answer.

5 0
3 years ago
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