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Svetlanka [38]
1 year ago
8

on 1: A piece of unknown metal weighs 348 g. When the metal piece absorbs 6.64 kJ of heat, its temperature increases from 22.4 °

C to 43.6 °C.
Chemistry
2 answers:
Ede4ka [16]1 year ago
6 0

Answer:

.900 J / g-C°

Explanation:

I assume you are looking for the specific heat of the metal

Specific heat =  J / g-C

                      = 6640 J / 348 g[ (43.6 - 22.4) ] = .900 J / g-C

aivan3 [116]1 year ago
3 0

Answer:

.900 J / g-C°

Explanation:

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  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 9.75526 \cdot 10^{24} \ molecules \ H_2O

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