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Svetlanka [38]
2 years ago
8

on 1: A piece of unknown metal weighs 348 g. When the metal piece absorbs 6.64 kJ of heat, its temperature increases from 22.4 °

C to 43.6 °C.
Chemistry
2 answers:
Ede4ka [16]2 years ago
6 0

Answer:

.900 J / g-C°

Explanation:

I assume you are looking for the specific heat of the metal

Specific heat =  J / g-C

                      = 6640 J / 348 g[ (43.6 - 22.4) ] = .900 J / g-C

aivan3 [116]2 years ago
3 0

Answer:

.900 J / g-C°

Explanation:

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Convert using the relation ship below
olga2289 [7]

Answer:

25.33125KPa

Explanation:

From the above,

1atm = 101.325KPa

0.25atm = (0.25atm x 101.325KPa) / 1atm = 25.33125KPa

Therefore, 0.25atm = 25.33125KPa

5 0
3 years ago
A 75.0 mL 75.0 mL aliquot of a 1.70 M 1.70 M solution is diluted to a total volume of 278 mL. 278 mL. A 139 mL 139 mL portion of
Vlada [557]

Answer:

0.210 M

Explanation:

<em>A 75.0 mL aliquot of a 1.70 M solution is diluted to a total volume of 278 mL.</em>

In order to find out the resulting concentration (C₂) we will use the dilution rule.

C₁ × V₁ = C₂ × V₂

1.70 M × 75.0 mL = C₂ × 278 mL

C₂ = 0.459 M

<em>A 139 mL portion of that solution is diluted by adding 165 mL of water. What is the final concentration? Assume the volumes are additive.</em>

Since the volumes are additive, the final volume V₂ is 139 mL + 165 mL = 304 mL. Next, we can use the dilution rule.

C₁ × V₁ = C₂ × V₂

0.459 M × 139 mL = C₂ × 304 mL

C₂ = 0.210 M

7 0
3 years ago
Read 2 more answers
Using the information from STP or SATP conditions determine the value of the ideal gas constant.
Dovator [93]

Answer:

0.0821 atm.L/Kmol

Explanation:

At stp, the values temperature, pressure and volume is given below:

Pressure (P) = 1 atm

Temperature (T) = 273 K

Volume (V) = 22.4 L

At stp, 1 mole of a gas occupy 22.4L.

Number of mole (n) = 1 mole

Gas constant (R) =?

The ideal gas equation is given below:

PV = nRT.

With the above equation, the gas constant R can be obtained as follow:

1 atm x 22.4L = 1 mole x R x 273K

Divide both side by (1 mole x 273 K)

R = (1 atm x 22.4L) / (1 mole x 273 K)

R = 0.0821 atm.L/Kmol

Therefore, the gas constant is 0.0821 atm.L/Kmol

4 0
3 years ago
Hydrogen sulfide decomposes according to the following reaction, for which Kc=9.30E-8 at 700 degrees Celsius. 2 H2S(g) --&gt; 2
Svetlanka [38]

Answer: The equilibrium concentration of H_2(g) at 700 degrees Celsius is 0.0012 M

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c&#10;

Moles of  H_2S = 0.29 mole

Volume of solution = 3.0 L

Initial concentration of H_2S = \frac{0.29mol}{3.0L}=0.097M

The given balanced equilibrium reaction is,

                    2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

         Initial conc.         0.097 M           0M          0M

At eqm. conc.    (0.097-2x) M            (2x) M   (x) M

The expression for K_c is written as:

K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

K_c=\frac{(2x)^2\times x}{(0.097-2x)^2}

9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.097-2x)^2}

x=0.00060

Equilibrium concentration of [H_2]= 2x= 2\times 0.00060=0.0012M

6 0
3 years ago
According to the arrhenius concept, if HNO3, were dissolved in water, it would act as?: a. Proton acceptor b. A base c. A source
Alexxandr [17]
Arrhenius concept just states that if a solution dissociates and forms H+ ions then its and acid, but if it dissociates and forms OH- than it's a base.

So the answer to your question would be D. An Acid
5 0
3 years ago
Read 2 more answers
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