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SCORPION-xisa [38]
3 years ago
14

Dale says the ratios 3:5 and 2:10 are equivalent. Is He correct? Explain

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
3 0

Answer:

No, Dale Isn't correct because 3:5 is greater than 2:10

Step-by-step explanation:

3:5 and 2:10 is the same as in \frac{3}{5}  and \frac{2}{10}

First Find the least common denominator or LCM of the two denominators:

LCM of 5 and 10 is 10

Next, find the equivalent fraction of both fractional numbers with denominator 10

For the 1st fraction, since 5 × 2 = 10,

\frac{3}{5} =\frac{3*2}{5*2} =\frac{6}{10}

Likewise, for the 2nd fraction, since 10 × 1 = 10,

\frac{2}{10} =\frac{2*1}{10*1} =\frac{2}{10}

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

\frac{6}{10} >\frac{2}{10} Or\frac{3}{5} >\frac{2}{10}

Hence, \frac{3}{5} is <u>Greater than </u>\frac{2}{10}

Hence, 3:5 is <u>Greater than </u>2:10

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spayn [35]

Answer:

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Step-by-step explanation:

The other addend is determined by subtracting -5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5 from 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2:

x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b + 2 - (-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b -5)

x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +2 +5\cdot a^{2}\cdot b^{2}-12\cdot a^{2}\cdot b+5

x = (10\cdot a^{2}\cdot b^{2}+5\cdot a^{2}\cdot b^{2})-(8\cdot a^{2}\cdot b+12\cdot a^{2}\cdot b)+6\cdot a \cdot b^{2}-4\cdot a \cdot b +7

x = 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7

The other addend is 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7.

6 0
3 years ago
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<span>This must be your answer:
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