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Viefleur [7K]
3 years ago
6

Study the graphs in Figure 6.33 and answer these questions. (see attached image)

Chemistry
1 answer:
Vlad [161]3 years ago
6 0

Hey there :)

The highest solubility of a solute will be when it has the greatest quantity in g when dissolved in 100 g of water. So the solute that is most soluble in water, will have a higher g/100 g water.

1:

a: 0°C - Sucrose will be the solute that is most soluble in water.

b: 80 °C - Also Sucrose will be the most soluble in water.

2:

Yes, as we can see in the graph, sucrose, potassium nitrate, ammonium sulfate and sodium chloride have different solubilities between them and at different temperatures. For example, solubility at 0 °C:

sucrose: 180 g / 100 g of water

potassium nitrate: ~10 g/ 100 g of water

ammonium sulfate: 80 g/100 g water

sodium chloride: 30 g/ 100 g of water

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pochemuha

Answer:

By heating the solution

Explanation:

Physical changes and chemical changes are the two types of changes that a substance undergoes. Physical change does not alter the substance's chemical composition, hence, can be easily reversed. There is also no new product formed. This is contrary to the occurrences of a chemical change, which cannot be reversed after a new product has been formed.

A physical change is what occurs when Adrian's teacher dissolves some sugar in a beaker of water to form a sugar solution. This change does not involve any new product formation, hence, can be reversed. The sugar can be derived back from the solution by HEATING THE SOLUTION. The water (solvent) will evaporate and the sugar (solute) will precipitate.

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3 years ago
Which Pair Of Compounds Are Isomers?
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Answer:

D. water

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5. A box with a volume of 22.4 L contains 1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C. Which of the following statements
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B. The partial pressure of N2 is 101 kPa

<h3>Further explanation</h3>

Given

volume = 22.4 L

1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C

Required

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Solution

Ideal gas law :

PV = nRT

n total = 3 mol

T = O °C + 273 = 273 K

P = nRT/V

P = 3 x 0.08205 x 273 / 22.4

P total = 3 atm = 303,975 kPa

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P Hydrogen = 2/3 x 303.975 = 202.65 kPa

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