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Viefleur [7K]
3 years ago
6

Study the graphs in Figure 6.33 and answer these questions. (see attached image)

Chemistry
1 answer:
Vlad [161]3 years ago
6 0

Hey there :)

The highest solubility of a solute will be when it has the greatest quantity in g when dissolved in 100 g of water. So the solute that is most soluble in water, will have a higher g/100 g water.

1:

a: 0°C - Sucrose will be the solute that is most soluble in water.

b: 80 °C - Also Sucrose will be the most soluble in water.

2:

Yes, as we can see in the graph, sucrose, potassium nitrate, ammonium sulfate and sodium chloride have different solubilities between them and at different temperatures. For example, solubility at 0 °C:

sucrose: 180 g / 100 g of water

potassium nitrate: ~10 g/ 100 g of water

ammonium sulfate: 80 g/100 g water

sodium chloride: 30 g/ 100 g of water

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A reactant decomposes with a half-life of 129 s when its initial concentration is 0.380 M. When the initial concentration is 0.5
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Answer:

A) The rate constant is 0.0078 s^-1

B) The order of the reaction is 1

Explanation:

A) Rate constant (k) = Rate ÷ final concentration

Rate = change in concentration/half-life

Initial concentration of reactant = 0.38 M

Half-life is the time taken for the reactant to decompose to half of its initial concentration = 129 s

Final concentration = 1/2 × 0.38 = 0.19 M

Change in concentration = 0.38 - 0.19 = 0.19 M

Rate = 0.19/129 = 0.0015 M/s

Rate constant (k) = 0.0015 M/s ÷ 0.19 M = 0.0078 s^-1

B) Rate = kC^n

n is the order of the reaction

0.0015 = 0.0078×0.19^n

0.19^n = 0.0015/0.0078

0.19^n = 0.19

Log 0.19^n = Log 0.19

nLog 0.19 = Log 0.19

n = Log 0.19/Log 0.19 = 1

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