Optrion A: when trying to determine a star's chemical composition.
Because unique atomic emission spectrum, analyzing the emission spectrum you can tell the chemical composition.
Answer:
false
Explanation:
cuz carbon dioxide is greenhouse gasses
Answer:
![Kc=0.14](https://tex.z-dn.net/?f=Kc%3D0.14)
Explanation:
Hello,
In this case, for the given reaction, the equilibrium expression is:
![Kc=\frac{[NO]^2[O_2]}{[NO_2]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BNO%5D%5E2%5BO_2%5D%7D%7B%5BNO_2%5D%5E2%7D)
That in terms of the reaction extent
is written as (initial concentration of NO2 is 0.24 M for 0.24 mol in 1.00 L):
![Kc=\frac{(2*x)^2(x)}{(0.24M-2*x)^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%282%2Ax%29%5E2%28x%29%7D%7B%280.24M-2%2Ax%29%5E2%7D)
Moreover, since at the equilibrium 0.14 moles of NO are present (a 0.14-M concentration), we can compute the reaction extent as shown below:
![[NO]=2*x=0.14M](https://tex.z-dn.net/?f=%5BNO%5D%3D2%2Ax%3D0.14M)
![x=0.14M/2=0.07M](https://tex.z-dn.net/?f=x%3D0.14M%2F2%3D0.07M)
In such a way, knowing
, we compute Kc as shown below:
![Kc=\frac{(2*0.07)^2(0.07)}{(0.24M-2*0.07)^2}\\\\Kc=0.14](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%282%2A0.07%29%5E2%280.07%29%7D%7B%280.24M-2%2A0.07%29%5E2%7D%5C%5C%5C%5CKc%3D0.14)
Regards.
The problem above is simply a conversion problem. We only need a conversion factor to convert the units from amu to kg. From a conversion table, we will see that 1 amu is equal to 1.66x10^-27 kg. We convert as follows:
0.13261 amu ( <span>1.66 × 10^-27 kg / 1 amu ) = 2.20x10^-28 kg </span>
Answer:
1. Protons
2. Electrons
3. Neutrons
4. Protons and neutrons
5. Electrons
Explanation:
The protons are the only positive sub-atomic particles and the have a charge of +1.
The Electrons are the only negative subatomic particles and they have a charge of -1
Neutrons do not have any charge but they have the same mass as the protons
The nucleus of an atom is where most of the atomic masses are concentrated and it houses the neutrons and protons
The electrons reside outside the nucleus and they have a much more lesser mass compared to the neutrons and protons