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Sergio [31]
2 years ago
15

Determine the height h of water that will support 1atmosphere pressure (Hint: 1 = = ).

Physics
1 answer:
maw [93]2 years ago
5 0

Answer:

Just Keep Scrolling You'll See My Answer

Hope Its Helps Bro:)

brainliest me

\red{ \rule{0pt}{100000pt}} \orange{ \rule{0pt}{100000pt}} \color{yellow}{ \rule{0pt} {100000pt}} \green{ \rule{0pt} {100000pt}} \blue{ \rule{0pt} {100000pt}} \purple{ \rule{0pt} {100000pt}}

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A person who weighs 69kg rides with an acceleration of +1.45 m/s2. What is the force exerted by the legs on the person's upper b
trapecia [35]

Answer:

The force exerted by the legs on the person's upper body 32.106 N.

Given:

Mass = 69 kg

Acceleration = 1.45 \frac{m}{s^{2} }

To find:

Force exerted by legs on the person's upper body = ?

Formula used:

Force = mass × acceleration

Solution:

Mass of legs = \frac{32}{100} mass of body

Mass of legs = 22.08 kg

According to Newton's second law of motion,

Force = mass × acceleration

Force = 22.08 × 1.45

Force = 32.106 N

The force exerted by the legs on the person's upper body 32.106 N.

4 0
4 years ago
you decide to measure the mass of an aircraft carrier in the CGS system.What unit does your measurement end up in?
Pavel [41]
Pounds I believe? if not then I recommend google :)
6 0
4 years ago
I have always wondered if the saying it was hot enough to fry an egg on the sidewalk could 20 points be true. Please describe ho
ikadub [295]

Answer:

This is one of the hottest summers America has ever seen and Jeremiah Warren is taking advantage of the heat wave and doing a little cooking…in his car!

It was about 98 or 99 degrees in Texas, so Jeremiah thought he’d head outside to see if it was hot enough to actually cook food.  He buttered up a frying pan on his dashboard and filled it with an egg, cookie dough, a hot dog and bacon (mmm…bacon!).  He set up another frying pan on the sidewalk and a few hours later he came back for a mid-day snack.

Explanation:

4 0
3 years ago
An air-track cart is attached to a spring and completes one oscillation every 5.67 s in simple harmonic motion. at time t = 0.00
Masteriza [31]
The cart is moving by simple harmonic motion, and its position at time t is described by
x(t) = A \cos (\omega t)
where
A is the amplitude of the oscillation
\omega is the angular frequency

The amplitude of the oscillation corresponds to the maximum displacement of the spring, which corresponds to the initial position where the spring was released: 
A=0.250 m

The period of the motion is T=5.67 s, and the angular frequency is related to the period by
\omega =  \frac{2 \pi}{T}= \frac{2 \pi}{5.67 s} =1.11 rad/s

Therefore now we can calculate the position of the system at the time t=29.6 s:
x(29.6 s)=(0.250 m)\cos ((1.11 rad/s)(29.6 s))=+0.033 m
3 0
3 years ago
Read 2 more answers
Megan walks 1100 m to the left in 330s. What was her average speed in m/s?
Hunter-Best [27]

Answer:

3.33m/s

Explanation:

Speed is the change in distance of a body with respect to time.

Speed = Distance/Time

Given

Distance = 1100m

Time = 330s

Speed = 1100/330

Speed = 3.33m/s

Hence her average speed in m/s is 3.33m/s

7 0
4 years ago
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