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spin [16.1K]
3 years ago
6

Can you please help me!!! I need this answered before midnight

Mathematics
1 answer:
Allisa [31]3 years ago
8 0
4x=9y+2
x=(9y+2)/4
11x-8=90+9y+2
11((9y+2)/4)-8=9y+92
(99y+22)/4=9y+100
99y+22=36y+400
63y=378
y=6
x=14
is the question asking for y or x??or is it asking for angle

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Your friend has improved in his math class. On his first test he scored 50 points, and then he scored 53, 56, 59, and 62 points
emmainna [20.7K]

Answer:

Step-by-step explanation: I think you skip count by 50s or something like that. So, it has to be 64.

3 0
3 years ago
Limit   
STatiana [176]

Rationalize the numerator:

\dfrac{\sqrt{x+4}-2}x\cdot\dfrac{\sqrt{x+4}+2}{\sqrt{x+4}+2}=\dfrac{(\sqrt{x+4})^2-2^2}{x(\sqrt{x+4}+2)}=\dfrac x{x(\sqrt{x+4}+2)}=\dfrac1{\sqrt{x+4}+2}

This is continuous at x=0, so we can evaluate the limit directly by substitution:

\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14

5 0
3 years ago
I’ll award you brainliest if you answer This question
guajiro [1.7K]

Answer:

$2353 at 12.5% and $7647 at 8.25%

Step-by-step explanation:

I'll say a is the amount he invested in one market, and b is the amount in the other.

a + b = 10000, or b = 10000 - a

multiplying the investments with the percentages and adding them together will give the total earned interest.

(a × 0.125) + (b × 0.0825) = 925

0.125a + 0.0825b = 925

Use substitution to solve for a.

0.125a + 0.0825(10000 - a) = 925

0.125 a + 825 - 0.0825a = 925

0.0425a = 100

a = 2352.94

Use substitution to find b

b = 10000 - 2352.94

b = 7647.06

The questions are to the nearest dollar so round a and b.

$2353 and $7647

6 0
3 years ago
Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.2 centimeters (
MAVERICK [17]

Answer:

The interval [32.6 cm, 45.8 cm]

Step-by-step explanation:

According with the <em>68–95–99.7 rule for the Normal distribution:</em>  If \large \bar x  is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval

\large [\bar x - s, \bar x +s]

around 95% of the data must fall in the interval

\large [\bar x -2s, \bar x +2s] 

around 99.7% of the data must fall in the interval

\large [\bar x -3s, \bar x +3s]

So, the range of lengths that covers almost all the data (99.7%) is the interval

[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]

<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>

3 0
3 years ago
If a,b, and c are prime numbers, do (a+b)(a+b) and cc have a common factor that is greater than 1?
Tanya [424]

Answer:

1. Information is not sufficient

2. Information is not sufficient

Step-by-step explanation:

Question Modified

If a,b, and c are prime numbers, do (a+b) and c have a common factor that is greater than 1?

(1) a,b, and c are all different prime numbers

(2) c≠2

Explanation

1. Let's assume values of 1,3 and 5 to a, b, and c respectively

a + b = 1+3 = 4

4 and 5 do not have any common factor aside 1

Let's assume values of 1,3 and 2 to a,b and c respectively

a + b = 1+3 = 4

4 and 2 have a common factor of 2

So, the available information is not sufficient

2.

Let's assume values of 2,7 and 3 to a b and c response

a + b = 2 + 7 = 9

9 and 3 have a common factor of 3

Also, let's assume values of 2,7 and 5 to a, b and c

a + b = 2 + 7 = 9

9 and 5 do not have a common factor

So, the available information is also not sufficient to answer the question.

3 0
3 years ago
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