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Alex787 [66]
3 years ago
15

Someone help me with the steps please

Mathematics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

Let u=3x^2-3x

Solution: \frac{1}{6} \sqrt{3x^2-3x}+C

Step-by-step explanation:

See attached for step-by-step

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Travka [436]

Answer:

comunest hahahahaha

Step-by-step explanation:

4 0
4 years ago
If f(x) = 2x2 - x - 6 and g(x) = x2 - 4, find f(x) ÷ g(x).
Phantasy [73]

f(x)=2x^2-x-6,\ g(x)=x^2-4\\\\f(x)\div g(x)=\dfrac{f(x)}{g(x)}=\dfrac{2x^2-x-6}{x^2-4}=\dfrac{2x^2-4x+3x-6}{x^2-2^2}\\\\=\dfrac{2x(x-2)+3(x-2)}{(x-2)(x+2)}=\dfrac{(x-2)(2x+3)}{(x-2)(x+2)}=\dfrac{2x+3}{x+2}\ for\ x\neq0\\\\Answer:\ f(x)\div g(x)=\dfrac{2x+3}{x+2}

Used:\ a^2-b^2=(a-b)(a+b)

4 0
3 years ago
-1/2+ 7/8- 1/10<br><br> Hint: rational numbers
ki77a [65]

After solving -\frac{1}{2}+\frac{7}{8}-\frac{1}{10}\\ we get \frac{11}{40}

Step-by-step explanation:

We need to solve the following expression:

-\frac{1}{2}+\frac{7}{8}-\frac{1}{10}\\

Solving the above expression we need to find the LCM of denominators: 2,8,10

The LCM of 2,8,10 is 40

-\frac{1}{2}+\frac{7}{8}-\frac{1}{10}\\=\frac{-1*20+7*5-1*4}{40}\\=\frac{-20+35-4}{40}\\=\frac{11}{40}

So, after solving -\frac{1}{2}+\frac{7}{8}-\frac{1}{10}\\ we get \frac{11}{40}

Keywords: Rational Numbers

Learn more about Rational Numbers at:

  • brainly.com/question/4390083
  • brainly.com/question/357905
  • brainly.com/question/12817595

#learnwithBrainly

3 0
3 years ago
How do you make .208 a fraction?
seropon [69]
0.\underbrace{208}_{3}=\frac{208}{1\underbrace{000}_3}=\frac{208}{1000}\\\\divide\ a\ numerator\ and\ a\ denominator\ by\ 8\\\\\frac{208}{1000}=\frac{26}{125}\\\\Answer:0.208=\frac{26}{125}
6 0
4 years ago
Find the horizontal asymptote for y= 5x/x+6 . <br> y = 0 <br> y = −6<br> none<br> y = 5
gayaneshka [121]

Answer:

y

=

5

x

x

+

6

Find where the expression

5

x

x

+

6

is undefined.

x

=

−

6

Consider the rational function

R

(

x

)

=

a

x

n

b

x

m

where

n

is the degree of the numerator and

m

is the degree of the denominator.

1. If

n

<

m

, then the x-axis,

y

=

0

, is the horizontal asymptote.

2. If

n

=

m

, then the horizontal asymptote is the line

y

=

a

b

.

3. If

n

>

m

, then there is no horizontal asymptote (there is an oblique asymptote).

Find

n

and

m

.

n

=

1

m

=

1

Since

n

=

m

, the horizontal asymptote is the line

y

=

a

b

where

a

=

5

and

b

=

1

.

y

=

5

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes:

x

=

−

6

Horizontal Asymptotes:

y

=

5

No Oblique Asymptotes

image of graph

5 0
2 years ago
Read 2 more answers
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