Answer:
19.02173913043478
Step-by-step explanation:
Answer:
140
Step-by-step explanation:
When working HCF and LCM problems, I like to think in terms of this little diagram:
(a [ b ) c]
It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.
__
Here, we're given ...
b = 20
ab = 320
abc = 2240
Then ...
c = abc/(ab) = 2240/320 = 7
x = bc = 20(7) . . . . . . equivalently, x = (abc·b)/(ab) = (2240·20)/320
x = 140
Answer:
(c) III
Step-by-step explanation:
If you simplify the equations and the left side is identical to the right side, then there are an infinite number of solutions: the equation is true for all values of x.
Another way to simplify the equation is to subtract the right side from both sides. If that simplifies to 0 = 0, then there are an infinite number of solutions.
__
<h3>I. </h3>
2x -6 -6x = 2 -4x . . . . eliminate parentheses
-4x -6 = -4x +2 . . . . no solutions (no value of x makes this true)
__
<h3>II.</h3>
x +2 = 15x +10 +2x . . . . eliminate parentheses
x +2 = 17x +10 . . . . one solution (x=-1/2)
__
<h3>III.</h3>
4 +6x = 6x +4 . . . . eliminate parentheses
6x +4 = 6x +4 . . . . infinite solutions
__
<h3>IV.</h3>
6x +24 = 2x -4 . . . . eliminate parentheses; one solution (x=-7)
<span>Volume of the Sphere V = 4/3pi x r^3
So when diameter d = 3 inches => r = 1.5 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 1.5^3 = 14.14 in
So when diameter d = 8 inches => r = 4 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 4^3 = 268.03 in
So when diameter d = 9 inches => r = 4.5 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 4.5^3 = 381.63 in
value for option (a) is 3 x 14.14 = 42.42 inches
value for option (b) is 268.03 inches
value for option (c) is 381.63 / 2 = 190.815 inches
So the correct option would be (b)</span>
Answer:
y^6
Step-by-step explanation:

=
