Answer:
256/3 = 85 1/3 square inches
Step-by-step explanation:
The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...
A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches
The sum of an infinite series with first term 64 and common ratio 1/4 is ...
S = a1/(1 -r) . . . . . . for first term a1 and common ratio r
= 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches
The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.
Answer:
When x = 4, (4, 0)
When y = 4, (6, 4)
Step-by-step explanation:
To find the ordered-pair solution when x = 4, plug 4 into the x of the equation.
y = 2x - 8
y = 2(4) - 8
y = 8 - 8
y = 0
This produces the ordered pair (4, 0).
To find the ordered-pair solution when y = 4, plug 4 into the y of the equation.
y = 2x - 8
4 = 2x - 8
12 = 2x
6 = x
x = 6
This produces the ordered pair (6, 4).
Answer:
C = 600 + 50s
Step-by-step explanation:
The students are planning to visits the Canada's wonderland. The students will spend a full day at the park.
The entry fee for each student is $50 and the bus cost is $600. Each student will pay $50 for entry into the park.
Let
the number of student = s
cost of the trip = C
Relating the variable C and s
The total amount of money the student will pay for entry fee = 50 × s = 50s
Therefore, cost of the trip can be expressed as follows
C = 600 + 50s
Answer:
Original number is 47
Step-by-step explanation:
Given: The tens digit is three less than the units digit. If the digits are reversed, the sum of the reversed number and the original number is 121.
To find: the original number
Solution:
Let x denotes digit at ones place.
As the tens digit is three less than the units digit,
Digit at tens place = 
Original number = 
When digits are reversed,
Reversed number = 
As the sum of the reversed number and the original number is 121,
So,
original number = 
