Take x-2 and insert it into 2x^2 + 3x-2 where the x is located
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2
Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2 = x^2 -4x + 4
2(x-2)^2 = 2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8
Now that 2(x-2)^2 is done lets move on to 3(x-2).
Use the distributive property and distribute the 3
3(x-2) = 3x - 6
All that is left is the -2
Now lets put it all together
2(x-2)^2 + 3(x-2)-2
2x^2 - 8x + 8 + 3x - 6 - 2
Now combine all our like terms
2x^2 - 8x + 8 + 3x - 6 - 2
Combine: 2x^2 = 2x^2
Combine: -8x + 3x = -5x
Combine: 8 - 6 - 2 = 0
So all we have left is
2x^2 - 5x
Answer: y>-3 and x is all real numbers
Answer:
2400 in^3
Step-by-step explanation:
Tyler asks for a fish tank for his birthday. The task he wants is a rectangular prism 20 inches long, 10 inches wide, and 12 inches tall. How much water will the fish tank hold?
the capacity of the tank can be determined by calculating the volume of the tank
volume of a prism = length x width x height
20 x 10 x 12 = 2400 in^3
Answer:
100 square inches
Step-by-step explanation:
Dimension of each of the ten pictures= 4 inches by 6 inches
Area of one of the pictures=4*6=24 Square Inch.
Total Area of the 10 pictures=24*10=240 Square Inches.
Dimension of the Poster Board=20 inches by 17 inches.
Area of the Poster Board=20*17=340 Square Inches.
Area not covered by the pictures=340-240=100 Square Inches
Therefore, 100 square inches of the green background will show after the pictures are mounted.
8x^4 + x^3 - 4x^2 +1. I believe the answer is B. Please correct me if I am wrong.
