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3 years ago

How do i solve using the rational root theorem. 2x3-9x2-11x+8=0

1 answer:

4 0

2(3)-9(2)-11x+8=0
(2)(3)-(9)(2)-11x+8=0
6+-18+-11x+8=0
(-11x)+(6+-18+8)=0 Combine Like Terms.
-11x+-4=0
-11x-4=0
Add 4 to both sides.
-11x-4+4=0+4
-11x=4
Divide both sides by -11.
-11x/-11=4/-11
x=-4/11

Hope this helps!

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steps below

Step-by-step explanation:

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f'(x) = 7x⁶ - 36x⁵ + 40x⁴

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