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Vlada [557]
3 years ago
14

How do i solve using the rational root theorem. 2x3-9x2-11x+8=0

Mathematics
1 answer:
Lapatulllka [165]3 years ago
4 0
2(3)-9(2)-11x+8=0
(2)(3)-(9)(2)-11x+8=0
6+-18+-11x+8=0
(-11x)+(6+-18+8)=0 Combine Like Terms.
-11x+-4=0
-11x-4=0
Add 4 to both sides.
-11x-4+4=0+4
-11x=4
Divide both sides by -11.
-11x/-11=4/-11
x=-4/11

Hope this helps!

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the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

4 0
3 years ago
Integer (-1) c (+5) =
LenKa [72]
-13.5914091423 is what I got from a calculator.
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9^(2-7)

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a negative exponent flips from the numerator to the denominator

1/ 9^5

Choice D

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I think the answer is 140
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When you view the pendulum’s swing, it shows that at the very top of the swing KE = 0. What does that tell you about the pendulu
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Answer:

The kinetic energy of an object is given by: Kinetic energy = 1/2 * mass * velocity If the kinetic energy of the pendulum at the top of its swing is 0, then this tells us that the velocity of the pendulum at that point is 0

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