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Alecsey [184]
2 years ago
9

Mass A forklift raises a box 1.2 m and does 7.0 kJ of work on it. What is the mass of the box?

Physics
1 answer:
Mamont248 [21]2 years ago
5 0

Answer:

Work and Kinetic Energy

A B

3. A 0.180 kg balls falls 2.5 m. How much work does the force of gravity do on the ball? 4.41 J

4. A forklift raises a box 1.2 m doing 7.0 kJ of work on it. What is the mass of the box? 595.24 kg

5. How much work does the force of gravity do when a 25 N object falls a distance of 3.5 m? 87.5 J

Explanation:

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What’s contact force ?
kodGreya [7K]

Explanation:

Contact force is any force that requires contact.  An object that exerts a force on another object by touching it is exerting a contact force.  Examples of contact force are friction and normal force.

Examples of a non-contact force are gravity and magnetism.

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2 years ago
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Please help with vectors (will give BRAINLIEST answer)
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just analyze it in this way:

20cos30*=10( radical 3 )

20sin30*=10

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3 years ago
You want to calculate the density of a marble what is one piece of data that you need A the weight B the volume C how fast the m
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C I think but I’m not really sure....
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En un viaje ida y vuelta de 10 kilómetros, el desplazamiento y la distancia recorrida son respectivamente.
Nataly [62]

Answer: creo que es A o D

Explanation:

8 0
2 years ago
on a very muddy football field, a 120 kg linebacker tackles an 75 kg halfback. immediately before the collision, the linebacker
Aleksandr-060686 [28]
B4 the tackle: 

<span>The linebacker's momentum = 115 x 8.5 = 977.5 kg m/s north </span>

<span>and the halfback's momentum = 89 x 6.7 = 596.3 kg m/s east </span>


<span>After the tackle they move together with a momentum equal to the vector sum of their separate momentums b4 the tackle </span>

<span>The vector triangle is right angled: </span>

<span>magnitude of final momentum = √(977.5² + 596.3²) = 1145.034 kg m/s </span>

<span>so (115 + 89)v(f) = 1145.034 ←←[b/c p = mv] </span>

<span>v(f) = 5.6 m/s (to 2 sig figs) </span>


<span>direction of v(f) is the same as the direction of the final momentum </span>

<span>so direction of v(f) = arctan (596.3 / 977.5) = N 31° E (to 2 sig figs) </span>


<span>so the velocity of the two players after the tackle is 5.6 m/s in the direction N 31° E </span>




<span>btw ... The direction can be given heaps of different ways ... N 31° E is probably the easiest way to express it when using the vector triangle to find it</span>
4 0
3 years ago
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