The power delivered by the motor lift in elevating the 10 passengers at the speed of 16.8 m/s is 205800 Watts
<h3>What is power? </h3>
Power is simply defined as the rate at which energy is consumed. It can be expressed mathematically as
Power (P) = Force (F) × velocity (v)
P = Fv
<h3>How to determine the force </h3>
- Mass (m) = 1250 Kg
- Acceleration due to gravity (g) = 9.8 m/s²
F = ma
F = 1250 × 9.8
F = 12250 N
<h3>How to determine the power </h3>
- Velocity (v) = 16.8 m/s
- Force (F) = 12250 N
P = Fv
P = 12250 × 16.8
P = 205800 Watts
Learn more about power:
brainly.com/question/5684937
Explanation:
You can simply subtract the atomic number from the mass number in order to find the number of neutrons. If the atom is neutral, the number of electrons will be equal to the number of protons.
Remember!
1. Your mass number is the total number of neutrons and protons within the atom.
2. Your atomic number is the amount of protons within the atom.
3. For neutral atoms, the electron number is the same as the atomic number.
Answer:
Find the attachments for complete solution
Answer:
the process by which a beam of light or other system of waves is spread out as a result of passing through a narrow aperture or across an edge, typically accompanied by interference between the wave forms produced. Diffraction refers to various phenomena that occur when a wave encounters an obstacle or opening. It is defined as the bending of waves around the corners of an obstacle or through an aperture into the region of geometrical shadow of the obstacle/aperture.
Explanation: FYI I gave you the def and what it refers to BTW
Answer:
Truck's speed = 5.21 m/s
Car's speed = 20.2 m/s
Explanation:
Given:
Mass of truck = M = 1650 kg
Speed of the truck initially = U = 15 m/s
Mass of the car = m = 779 kg
Initial speed of the car =u = 0
From the momentum conservation, Total initial momentum = Total final momentum.
M V+m U = M V +m v
⇒ (1650)(15) + 779×0 = (1650)V + 779 v
⇒ 24750 = 1650 V+779 v →(1)
Since the collision is elastic, relative velocity of approach = relative velocity of separation. 15 = v - V
⇒ v =V + 15; This is now substituted in the equation(1) above.
24750 = 1650 V + (799) (V+15)
⇒ 24750 = 1650 V + 799 V + 11985
⇒ 2449 V = 12765
⇒ Final velocity of the truck = 
= 5.21 m/s
Final velocity of the car = v = V+15 = 5.21 + 15 = 20.2 m/s
