Question

A car accelerates uniformly from rest to a speed of 7.6 m/s in 4.6 s. How far does the car travel in that time?

Answer 1

Answer:

The car will travel a distance of 17.45 meters.

Explanation:

Given:

Initial velocity $(V_i)$ = 0

Final velocity $(V_f)$ = 7.6 m/s

Time taken = 4.6 s

Acceleration = (Final velocity - Initial Velocity )/time

$a=\frac{(V_f-Vi)}{t}= \frac{7.6-0}{4.6}=1.65\ ms^-2$

We have to calculate total distance traveled by the car.

Let the distance traveled be 'd'

Equation of motion:

$d=V_i(t)+\frac{at^2}{2}$

Plugging the values.

⇒$d=V_i(t)+\frac{at^2}{2}$

⇒$d=0+\frac{1.65*(4.6)^2}{2}$

⇒$d=17.45\ m$

The car will travel a distance of 17.45 meters for the above case.