Check the picture below.
the area of the triangle whose base is AC and height is BD, is the same area of the triangle whose base is AB and altitude is BC, namely

Answer:
r = 3
Step-by-step explanation:
x^2 + 6x + y^2 - 8y = - 16
Take half the linear term and square it.
x^2 + 6x + (3)^2 + y^2 - 8y + (-4)^2 = - 16
Add the squared amounts to the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = - 16 + 9 + 16
Combine on the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = 9
Represent the 2 quadratics as perfect squares.
(x + 3)^2 + y - 4)^2 = 9
The radius is the square root of 9 which is 3
Answer:

Step-by-step explanation:
Begin with substuting the x variable with -2, we do this because the question has listed the value of x already.
Using the value of x, -2 we determine g(x).
g(x) = -2^2 + 2
Above is what the equation would look as, after you input the value of -2.
Using pemdas, (parantheses, exponents, multiplication, division, addition, subtraction) solve the equation.
-2^2 = 4
Think of it as -2 * -2, which is why -2^2 is 4.
Add 4 +2.
4 + 2 = 6.
Therefore, the value of g(x) = 6