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katen-ka-za [31]
4 years ago
12

2. Find the value of x for which l | | m.​

Mathematics
1 answer:
joja [24]4 years ago
7 0
2x-5=95 due to the alternate interior angles thm so you just add 5 to 95 to get 2x=100 then divide by 2 to get x=50!
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When solving quadratic equation, what do the X value stand for as it relates to plotting the graph of the equation?
Ber [7]

Step-by-step explanation:

step 1. The x values refer to the domain of the function.

step 2. if you set y = 0 and solve the quadratic equation the x values refer to the point the graph crosses the x axis.

7 0
3 years ago
If x = 2, y = 3 and z = 5, calculate the following: 5x - z
nikdorinn [45]
5*2 - 5
5*2=10
10-5=5
5 0
3 years ago
What is the meaning of the point (25, 20)?
Reil [10]

Answer:

(25, 20 ) represents that the dimension of the coral is 25 feet long and 20 feet wide.

Step-by-step explanation:

The general representation P(x,y) represents the Cartesian Representation of a point in a 2 Dimension.

Here, x represents the distance of the point   P from y axis to the x axis.

and y  represents the distance of the point   P from x axis to the y axis.

(x, y) together gives the  2 dimensional representation of the point P.

Now here, the given coordinates are (25, 20)

So, here x = 25 and y = 20

So, (25, 20 ) represents that the dimension of the coral  is 25 feet long and 20 feet wide.

Hence, option 3 is the most appropriate.

6 0
3 years ago
Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val
Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

e^{8r} = \frac{590}{330}

e^{8r} = 1.79

Applying ln to both sides:

\ln{e^{8r}} = \ln{1.79}

8r = \ln{1.79}

r = \frac{\ln{1.79}}{8}

r = 0.0726

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

A(t) = 330e^{0.0726t}

A(10) = 330e^{0.0726*10} = 682

The value of the account in the year 2009 will be $682.

4 0
4 years ago
A four-pack of 42-ounce ink cartridges sells for $85.99. The expression 42c represents the amount of ink in a number of cartridg
morpeh [17]

<span>I think it is A number of cartridges</span>
6 0
3 years ago
Read 2 more answers
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