All categories

2 years ago

HELP ASAP !!! I need the answer bad

Mathematics

1 answer:

Ann [662]2 years ago

7 0

Answer:

Sum of real parts: 12

Sum of imaginary parts: 3

Step-by-step explanation:

(22 − 5i) + (−10 + 8i)

Combine the real and imaginary parts in numbers 22 − 5i and −10 + 8i

22 − 10 + (−5 + 8)i

Add 22 to −10. Add −5 to 8

12 + 3i

So, the answer is:

Sum of real parts: 12

Sum of imaginary parts: 3i

The real part is 12, the imaginary part is 3

You might be interested in

5600 to the nearest 1000

dem82 [27]

Answer:

6000.

Step-by-step explanation:

Hundreds digit is 6 so we round up the thousand digit (5) to get 6000.

5 0

2 years ago

What are the roots of the equation? x^2+24=14×

defon

$\begin{gathered} x^2+24=14x \\ x^2-14x+24=0 \end{gathered}$

Therefore,

$\begin{gathered} x^2-14x+24=0 \\ x^2-2x-12x+24=0 \\ x(x-2)-12(x-2)=0 \\ (x-2)(x-12)=0 \\ x=2 \\ or\text{ } \\ x=12 \end{gathered}$

6 0

1 year ago

Find the length indicated

Contact [7]

Answer:

the answer is b, 12

Step-by-step explanation:

16-4=12

8 0

3 years ago

Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e

saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in $R^{2}$ . To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

$\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle$

Now, let's calculate each vector length by calculating the norm.

$\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86$

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0

4 years ago

a student found the slope of a line that passes through the point (-3,-10) and (5,-7) to be 3/8 what mistake did he make

In-s [12.5K]

The student didn't make any mistake. The slope of the line between those points is 3/8.

3 0

4 years ago