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3 years ago

Is it possible to tell if an acid or base is strong or weak just by looking at its chemical formula?

1 answer:

8 0

It is.

An acid will be strong when its conjugated base is highly stable, and vice-versa.

That can occur for instance through electronic delocalization.

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Assume that a daily diet of 2000 calories (i.e. 8.37 x 106 J) is converted completely to body heat.

slava [35]

Answer:

(a) the mass of the water is 3704 g

(b) the mass of the water is 199, 285.7 g

Explanation:

Given;

Quantity of heat, H= 8.37 x 10⁶ J

Part (a) mass of water (as sweat) need to evaporate to cool that person off

Latent heat of vaporization of water, Lvap. = 2.26 x 10⁶ J/kg

H = m x Lvap.

$m = \frac{H}{L._{vap}} =\frac{8.37 * 10^6.J}{2.26*10^6\ \frac{J}{kg}} = 3.704 \ kg$

mass in gram ⇒ 3.704 kg x 1000g = 3704 g

Part (b) quantity of water raised from 25.0 °C to 35.0 °C by 8.37 x 10⁶ J

specific heat capacity of water, C, 4200 J/kg.°C

H = mcΔθ

where;

Δθ is the change in temperature = 35 - 25 = 10°C

$m =\frac{H}{c* \delta \theta} = \frac{8.37 *10^6}{4200*10} = 199.2857 kg$

mass in gram ⇒ 199.2857 kg x 1000 g = 199285.7 g

5 0

3 years ago

Isotopes percent abundance of antimony

Nitella [24]

Antimony has two naturally occurring isotopes. Their abundance is given in the pic attached below

4 0

3 years ago

How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --> __ AlCl3 + __

kiruha [24]

Answer:

0.6258 g

Explanation:

To determine the number grams of aluminum in the above reaction;

determine the number of moles of HCl
determine the mole ratio,
use the mole ratio to calculate the number of moles of aluminum.
use RFM of Aluminum to determine the grams required.

<u>Moles </u><u>of </u><u>HCl</u>

35 mL of 2.0 M HCl

2 moles of HCl is contained in 1000 mL

x moles of HCl is contained in 35 mL

$x \: mol \: = \: \frac{2 \: \times \: 35}{1000} \\ = 0.07 \: moles \:$

We have 0.07 moles of HCl.

<u>Mole </u><u>ratio</u>

Balanced equation

6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)

Hence mole ratio = 6 : 2 (HCl : Al

but moles of HCl is 0.07, therefore the moles of Al;

$= \frac{2}{6} \times 0.07 \\ \: = 0.0233333 \: moles$

Therefore we have 0.0233333 moles of aluminum.

<u>Grams of </u><u>Aluminum</u>

We use the formula;

$grams \: = moles \: \times \: rfm$

The RFM (Relative formula mass) of aluminum is 26.982g/mol.

Substitute values into the formula;

$= 0.0233333 \: moles \: \times \: 26.982 \: \frac{g}{mol} \\ = 0.625799 \: grams$

The number of grams of aluminum required to react with HCl is 0.6258 g.

3 0

2 years ago

How does the kinetic energy of solids liquids and gases compare?

maksim [4K]

<h2> <em>QUESTION</em><em>:</em><em> </em><em>how does the kinetic energy of solids liquids and gases compare?</em></h2>

<h2> ANSWER:</h2><h3><em>Gases have the high kinetic energy because its particles are far apart from each other and have negligible fprce of attraction whereas liquids have high force of attraction as compared to gases so they have less kinetic energy then gases,and Solids have high force of attraction between its particles because of that its molecules are closely packed ,so solids do not have kinetic </em><em>energy.</em></h3><h2><em>HOPE</em><em> </em><em>IT </em><em>HELPS </em><em>YOU</em></h2>

4 0

2 years ago

Mr. Chem S. Tree added water to 250. ML of a 2.50 M NaOH solution, until the final volume was 500. ML. What is the new molarity

tresset_1 [31]

Answer:

molarity of diluted solution = 1.25 M

Explanation:

Using,

C1V1 (Stock solution) = C2V2 (dilute solution)

given that

C1 = 2.50M

V1 = 250ML

C2 = ?

V2 = 500ML

2.50 M x 250 mL = C2 x 500 mL

C2 = (2.50 M x 250 mL) / 500 mL

C2 = 1.25 M

Hence, molarity of diluted solution = 1.25 M

4 0

3 years ago