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Andreyy89
2 years ago
11

Calculate the number of moles in 7g of nitrogen gas​

Chemistry
1 answer:
Andru [333]2 years ago
5 0

Answer:

<h3>0.2498molN_{2}</h3>

Explanation:

7gN2 x \frac{1 mol}{2(14.01) g}

=0.2498mol N2

Nitrogen gas has the formula N_{2} so therefore that means you would have to multiply the mass in the molar by 2. To solve for the number of moles you need to cancel out the grams, you do this by using the molar mass of nitrgoen gas. You get the value on in the denominator from the periodic table (atomic mass of element). The grams will cancel out, leaving you with the number of moles when you divide 7/2(14.01).

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Evaluate the carbon dioxide molecule. Explain how to determine if double or triple bonds exist in the molecule.
S_A_V [24]

Answer:

It contain double Bond.

Explanation:

To determine weather the bond is double or triple simply check the electron involved in mutual sharing of an electron if 2 electron takes parts it said to be double or if 3 it said to be triple.

4 0
3 years ago
At 500K, the equilibrium constant for the reaction N2O4D2NO2 is 1.5 x 10^3. What is the equilibrium constant for the reaction: 6
Veronika [31]

Answer:

K = 2.96x10⁻¹⁰

Explanation:

Based on the initial reaction:

N2O4 ⇄ 2NO2; K = 1.5x10³

Using Hess's law, we can multiply this reaction changing K:

3 times this reaction:

3N2O4 ⇄ 6NO2; K = (1.5x10³)³ =3.375x10⁹

The inverse reaction has a K of:

6NO2 ⇄ 3N2O4 K = 1/3.375x10⁹;

<h3>K = 2.96x10⁻¹⁰</h3>

3 0
3 years ago
What is the volume of 2.0 mol CO2 at STP?
Andrew [12]

Answer:

44.8 litres is the answer to the question

6 0
2 years ago
A gas occupies a volume of 40.0 milliliters at 20 c if the volume is increased too 80.0 milliliters at constant pressure, the re
Troyanec [42]
Charles law gives the relationship between temperature and volume of gases. It  states that the volume of gas is directly proportional to temperature at constant pressure. 
V / T = k 
where V - volume and T - temperature in Kelvin and k - constant 
\frac{V1}{T1} =  \frac{V2}{T2}
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
T1 - 20 °C + 273 = 293 K
substituting these values in the equation 
\frac{40.0 mL}{293 K}  =  \frac{80.0 mL}{T}
T = 586 K
temperature in celsius = 586 K - 273 = 313 °C
new temperature is 313 °C
8 0
3 years ago
What mass of oxygen contains the same number of molecules as 42g of nitrogen?
lakkis [162]

Answer:

Given: 42 g of N2

Solve for O2 mass that contains the same number of molecules to 42 g of N2.

Solve for the number of moles in 42 g of N2

1 mole of N2 = (14 * 2) g = 28 g so the number of moles in 42 g of N2 is equal to 42 g / 28 g per mole = 1.5 moles

Solve for mass of 1 mole of oxygen

1 mole of O2 = 16 g * 2 = 32 g per mole

Solve for the mass of 1.5 moles of oxygen

mass of 1.5 moles of O2 = 32 g per mole * 1.5 moles

mass of 1.5 moles of O2 = 48 g

So 48 g of O2 contains the same number of molecules as 42 g of N2

3 0
3 years ago
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