10000 digits can be used for 4 digit A.T.M code.
<u>Solution:</u>
Given that A.T.M required 4 digit codes using the digits 0 to 9.
Need to determine how many four digit code can be used.
We are assuming that number starting with 0 are also valid ATM codes that means 0789 , 0089 , 0006 and 0000 are also valid A.T.M codes.
Now we have four places to be filled by 0 to 9 that is 10 numbers
Also need to keep in mind that repetition is allowed in this case means if 9 is selected at thousands place than also it is available for hundreds, ones or tens place .
First digit can be selected in 10 ways that is from 0 to 9.
After selecting first digit, second digit can be selected in 10 ways that is 0 to 9 and same holds true for third and fourth digit.
So number of ways in which four digit number is created = 10 x 10 x 10 x 10 = 10000 ways
Hence 10000 digits can be used for 4 digit A.T.M code.
16x + 33y = 260, I think this is correct. Hope this helps!:)
Answer:
15
Step-by-step explanation:
In this problem we need to use the numbers given. So in the problem it states that k = 20 and v = 10. We can replace the letters in the equation for the numbers that it equals so the equation can make sense so 25 - 20 + 10 because k is 20 and v is 10 I simply just replaced the letters with the numbers given in the problem. Then we can just subtract 25 - 20 which is 5 and add 10 which leaves you at a final answer of 15. Hope this helped!
There is no option of the box plots, so I have created a version that would represent this data.
To make the box plot you will need the lower extreme, lower quartile, median, upper quartile, and upper extreme.
Please see the attached picture.
3x - 2y = 20
Subtract 3y from both sides to get the y-variable on one side of the equal and the rest on the other.
-2y = - 3x + 20
Now divide by -2 on both sides to isolate the y-variable.
y = -3x/-2 + 20/-2
y = 3/2x - 10
