Question

What is the missing number if the mean of 48,33 is 41

Answer 1

Answer:

42

Step-by-step explanation:

let's make the missing number x

$mean = \frac{sum \: of \: numbers}{how \: many \: numbers \: there \: are}$

$41 = \frac{48 + 33 + x}{3}$

multiply 3 on both sides to get rid of the fraction, 41 × 3 = 123

$123 = 48 + 33 + x$

simplify the right side, 48 + 33 = 81

$123 = 81 + x$

subtract 81 on both sides

$123 - 81 = x$

$x = 42$