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Tju [1.3M]
2 years ago
11

In a game of pool, the cue ball moves at a speed of 2 m/s toward the eight ball. When the cue ball hits the eight ball, the cue

ball bounces off with a speed of 0.8 m/s at an angle of 20°, as shown in the diagram below. Both balls have a mass of 0.6 kg.
a. What is the momentum of the system before the collision? (Write it in component form.) (1 point)






b. What is the momentum of the system after the collision? (1 point)



c. Write the velocity of the cue ball after the collision in component form. (1 point)




















d. What is the x-component of the velocity of the eight ball after the collision? (2 points)















e. What is the y-component of the velocity of the eight ball after the collision? (2 points)















f. At what angle does the eight ball travel after the collision? (2 points)















g. What is the magnitude of the eight ball's velocity after the collision? (1 point)
Physics
1 answer:
damaskus [11]2 years ago
5 0
It’s should be c
Have a good day
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Answer:

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Explanation:

Applying,

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But,

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Where m = mass, g = acceleration due to gravity.

Substitute equation 2 into equation 1

M = mgd................. Equation 3

From the question,

Given: m = 3 kg, d = 20 cm = 0.2 m

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M = 3×0.2×9.8

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We have the relation

\dfrac{1^{\circ}C}{100}=\dfrac{15^{\circ}C}{h}+\left(-\frac{0.65}{100}\right)\\\Rightarrow \dfrac{1^{\circ}C}{100}+\left(-\frac{0.65}{100}\right)=\dfrac{15^{\circ}C}{h}\\\Rightarrow h=\dfrac{15^{\circ}C}{1.65^{\circ}C}\times 100\\\Rightarrow h=909.1\ m

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