Answer:
Speed of another player, v₂ = 1.47 m/s
Explanation:
It is given that,
Mass of football player, m₁ = 88 kg
Speed of player, v₁ = 2 m/s
Mass of player of opposing team, m₂ = 120 kg
The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :
![m_1v_1+m_2v_2=(m_1+m_2)V](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3D%28m_1%2Bm_2%29V)
V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.
![v_2=-\dfrac{m_1v_1}{m_2}](https://tex.z-dn.net/?f=v_2%3D-%5Cdfrac%7Bm_1v_1%7D%7Bm_2%7D)
![v_2=-\dfrac{88\ kg\times 2\ m/s}{120\ kg}](https://tex.z-dn.net/?f=v_2%3D-%5Cdfrac%7B88%5C%20kg%5Ctimes%202%5C%20m%2Fs%7D%7B120%5C%20kg%7D)
![v_2=-1.47\ m/s](https://tex.z-dn.net/?f=v_2%3D-1.47%5C%20m%2Fs)
So, the speed of another player is 1.47 m/s. Hence, this is the required solution.
The distance - time graph of the humming bird is missing, so i have attached it.
Answer:
Instantaneous velocity = 0.5 m/s
Explanation:
From the attached graph, at time t = 1 s, the corresponding distance is 0.5 m.
Instantaneous velocity is the velocity at that point.
Thus;
Instantaneous velocity = 0.5/1
Instantaneous velocity = 0.5 m/s
The only vector quantity on that list is displacement.
Answer:
How much kinetic energy does a 4 Kg cat have while running at 9 m/s?
its 5 J of kinetic energy.
Explanation: