Lewis structure for CH3CL
1 answer:
Answer:
The first step in forming the ch3cl lewis structure is drawing out all the atoms that exist within the molecule or ion being studied. Then, each atom must have its atomic number written above it. After this, draw lines between every bonded pair of non-identical electrons on adjacent atoms (bonded pairs are called “bonds”).
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Answer:
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Explanation:
The free energy of the reaction is given by :
where,
= standard Gibbs free energy
R = Gas constant =
T = temperature in Kelvins
K = equilibrium constant
We have :
1 kJ = 1000 J
T = 37.0 C = 37 +273.15 K = 310.15 K
Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Considering the reaction stoichiometry, the mass of H₂O that is produced when 11.9 moles of HNO₃ react is 107.1 grams.
<h3>Reaction stoichiometry</h3>The balanced reaction is:
3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Cu: 3 moles
- HNO₃: 8 moles
- Cu(NO₃)₂: 3 moles
- NO: 2 moles
- H₂O: 4 moles
The molar mass of the compounds present in the reaction is:
- Cu: 63.54 g/mole
- HNO₃: 63 g/mole
- Cu(NO₃)₂: 187.54 g/mole
- NO: 30 g/mole
- H₂O: 18 g/mole
Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:
Cu: 3 moles ×63.54 g/mole= 190.62 grams
HNO₃: 8 moles ×63 g/mole= 504 grams
Cu(NO₃)₂: 3 moles ×187.54 g/mole= 562.62 grams
NO: 2 moles ×30 g/mole= 60 grams
H₂O: 4 moles ×18 g/mole= 72 grams
<h3>Mass of H₂O produced</h3>It is possible to determine the the amount of mass of H₂O produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 72 grams of H₂O, if 11.9 moles of HNO₃ react how much mass of H₂O will be formed?
<u><em>mass of H₂O= 107.1 grams</em></u>
In summary, the mass of H₂O that is produced when 11.9 moles of HNO₃ react is 107.1 grams.
Learn more about reaction stoichiometry:
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