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Natasha_Volkova [10]
2 years ago
11

PLEASE HELP!! 50 POINTS FOR ONE MULTIPLE CHOICE QUESTION!!!!!!!!!!!!!!!

Chemistry
2 answers:
Paul [167]2 years ago
8 0

Answer:

it is B

Explanation:

Vlad1618 [11]2 years ago
6 0

Answer:

[B] 8 moles.

Explanation:

Chemical equation: N2 + H2 = NH3

  • N2 + 3H2 = 2NH3 (balanced)
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What is a difference between ferns and gymnosperms?
Otrada [13]

Answer:

The answer is below!!

Explanation:

Ferns are plants that do not bear flowers. They do not have any seeds as well. In this regard, their mode of reproduction is through spores. Gymnosperms on the other hand have seeds, although they are not put inside an ovary.

Hope I Helped!!

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7 0
2 years ago
Read 2 more answers
What is a wave produced by vibrating electric charges that can travel in matter and empty space?
Harman [31]
The answer is A

Explanation:
8 0
3 years ago
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The partial pressure of O2 in air at sea level is 0.21atm. The solubility of O2 in water at 20∘C, with 1 atm O2 pressure is 1.38
adell [148]

Answer:

1.21x10^{-3} M

Explanation:

Henry's law relational the partial pressure and the concentration of a gas, which is its solubility. So, at the sea level, the total pressure of the air is 1 atm, and the partial pressure of O2 is 0.21 atm. So 21% of the air is O2.

Partial pressure = Henry's constant x molar concentration

0.21 = Hx1.38x10^{-3}

H = \frac{0.21}{1.38x10^{-3} }

H = 152.17 atm/M

For a pressure of 665 torr, knowing that 1 atm = 760 torr, so 665 tor = 0.875 atm, the ar concentration is the same, so 21% is O2, and the partial pressure of O2 must be:

P = 0.21*0.875 = 0.1837 atm

Then, the molar concentration [O2], will be:

P = Hx[O2]

0.1837 = 152.17x[O2]

[O2] = 0.1837/15.17

[O2] = 1.21x10^{-3} M

7 0
3 years ago
You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans
OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

where:

Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

Vi = 16.7 mM * 4.5 l / 518 mM

<u>Vi = 0.145 l or 145 ml</u>

Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

4 0
3 years ago
If the lungs of a child hold 0.11 mol of air in a volume of 2.8 L, then the lungs of an average female adult, with a volume is 4
Aleks [24]

Answer:

Explanation:

A childs lung can hold .11mols/ per 2.8 L so that gives us a molarity of .039M

A adults lungs can hold .18 mols /per 4.6 so that gives us .039M aswell meaining that the lung capacity between the two is not different.

4 0
2 years ago
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