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Answer:
The answer to your question is 6.0 moles of O₂
Explanation:
Data
2KClO₃ ⇒ 2KCl + 3O₂
moles of O₂ = ?
moles of KCl = 4
Process
To find the number of moles of O₂, use proportions and cross multiplication.
Use the coefficients of the balanced equation.
2 moles of KCl ----------------- 3 moles of O₂
4 moles of KCl ----------------- x
x = (4 x 3) / 2
-Simplification
x = 12/2
-Result
x = 6 moles of O₂
-Conclusion
When 4,0 moles of KCl are produced, 6.0 moles of O₂ will be produced.
The correct answer is:
D) a chemical change produces a new substance by breaking and forming new bonds
Mass percent is the estimation of the mass of the element in a compound in percentage form. The mass % of manganese (Mn) in potassium permanganate is 34.76 %.
<h3>What is the mass percentage?</h3>
The mass percentage is defined by dividing the mass of the element by the molecular mass of the compound followed by multiplying it by 100%. It is given as,
Mass % = (Atomic Mass of element ÷ Molecular Mass) × 100
As it is known that,
Atomic Mass of manganese = 54.94 g/mol
Molecular Mass of potassium permanganate = 158.034 g/mol
Substituting values to calculate mass % as:
% Mn = (Atomic Mass of Mn ÷ Molecular Mass of KMnO₄) × 100
= (54.94 g/mol ÷ 158.034 g/mol) × 100
= 34.76 %
Therefore, 34.76% Mn is present in KMnO₄.
Learn more about mass percentage, here:
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