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Artemon [7]
3 years ago
13

Which process in the light-dependent reactions results in the release of hydrogen ions, electrons, and oxygen?

Chemistry
2 answers:
Otrada [13]3 years ago
8 0

Answer:

Water spit occurs during release of hydrogen ions,electrons and oxygen.

Explanation:

During  photosynthesis,water is required to be occured.The light activated the chlorophyll during light reactions,This activated chlorophyll molecule will results in splitting of water molecules,as a result water splits into hydrogen,oxygen and electrons.This process is known as photolysis.Hence water splitting occurs during light dependent reactions in release of hydrogen ions,electrons and oxygen.

tino4ka555 [31]3 years ago
6 0
The answer is actually Water Splitting! Hope this works:D
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Answer:

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Explanation:

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A solution is made by mixing 33.0 ml of ethanol, C2H6O and 67.0 ml of water. Assuming ideal behavior, what is the vapor pressure
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<span>Moles ethanol = 26.037 gms / 46 gms/mole = .57 moles </span>

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<span>total moles = .57 + 3.72 = 4.29 moles </span>

<span>Mole fraction ethanol = .57 moles ethanol / 4.29 moles total = 0.13</span>

<span>Moles fraction water = 3.72 moles water / 4.29 moles total = 0.87</span>

<span>Partial pressure of ethanol = mole fraction ethanol (.13) _ times VP ethanol 43.9 torr) = 5.707 torr </span>

<span>partial pressure water = mole fraction water .87) times VP water (l7.5 torr) = 15.23 torr </span>

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umka21 [38]

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Explanation:

The dependence of the reaction rate on the concentration of the reactants is given by the reaction order of each one, as shown in the rate equation.

Rate=k.[A]^{x} .[B]^{y} .[C]^{z}

where,

k is the rate constant

x, y, z are the reaction orders.

  • <em>The rate of reaction is not affected by changing the concentration of species A.</em> This means that the reaction order for A is x = 0 since when its concentration changes, the rate stays the same.
  • <em>Leaving all other factors identical, doubling the concentration of species B increases the rate by a factor of 4.</em> This means that the reaction order for B is y = 2, so when the concentration is doubled, the new rate is 2² = 4 times the initial rate.
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All in all, the rate equation is:

Rate = k . [B]² . [C]

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