When a water vapor condenses, heat is being released from the process. This heat is called latent heat of vaporization since the phase change happens without any change in the temperature. This value is constant per mole of a substance as a function of pressure and temperature. For this problem, we are given the heat of vaporization at a certain T and P. We use this value to calculate the total heat released from the process. We calculate as follows:
Total heat released: 32.4 g ( 1 mol / 18.02 g ) (40.67 kJ / mol) = 73.12 kJ
Therefore, 73.12 kJ of heat is released from the condensation of 32.4 g of water vapor.
Kilometers, Meters and centimeters if metric
Feet, inches, yards and miles if customary ( u.s.)
Answer:
A number is right I think
Answer:
losing valence electrons
Explanation:
please Mark as BRAINLIST answer
Answer:
The reaction is spontaneous when T> 0.98 Kelvin OR T> -272.17°C
Explanation:
Step 1: Data given
ΔH = 131.3 kJ/mol = 131300 J/mol
ΔS = 133.6 J/K*mol
T = 298K
Step 2: The balanced equation
C (s) + H2O (g) --> CO (g) + H2 (g)
Step 3: ΔG
For a reaction to be spontaneous, ΔG should be <0
When ΔG > 0 the reaction is spontaneous in the reverse direction.
ΔG = ΔH - TΔS
Since ΔG<0
ΔH - TΔS <0
Step 4: Calculate T where the reaction is spontaneous
ΔH - TΔS <0
131300 J/mol - T*133.6 J/K*mol <0
- T*133.6 J/K*mol < -131300 J/mol
-T <-131300 /133.6
-T< -982.8 Kelvin
T> 982.8 Kelvin OR T> 709.6°C
The reaction is spontaneous when T> 982.8 Kelvin OR T> 709.6°C
At 298 K this reaction C (s) + H2O (g) --> CO (g) + H2 (g) is <u>not spontaneous</u>
