During an experiment,what is the factor you are testing called

Particles are close to each other but can still slide past each other

scoray [572]

It is True. Hope this helped.

8 0

3 years ago

If Brian and his scooter had a mass of 50 kg, how much force would it take for him to accelerate at 0.8 m/s2

OleMash [197]

Answer:

<h2>The answer is 40 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 50 kg

acceleration = 0.8 m/s²

We have

Force = 50 × 0.8

We have the final answer as

Hope this helps you

8 0

3 years ago

A new gel is being developed to use inside padding and helmets to cushion the body from impacts. The gel is stored in a 4.24.2 c

alexira [117]

Answer:

The specific gravity of the gel is 1470.68

Explanation:

Given:

Volume $V = 4.24$ $m^{3}$

Diameter of tank $d = 2$ m

Pressure at surface $P _{o} = 1.41$ atm

Height $h = 6565$ ft $= \frac{6565}{3.281} = 2001$ m

Pressure at bottom is given by,

$P_{bottom} = \rho _{w} g h$

Where $\rho _{w} = 1000 \frac{kg}{m^{3} }$ , $g = 9.8\frac{m}{s^{2} }$

$P_{bottom} = 1000 \times 9.8 \times 2001$

$P_{bottom} = 19.6 \times 10^{6}$ $\frac{N}{m^{2} }$

Here volume is 4.24 $m^{3}$

$\pi r^{2} h = 4.24$

$h = \frac{4.24}{3.14} = 1.35$ m

From pascal equation,

$P_{bottom} = P_{o} + \rho _{gel} g h$

Find density of gel from above equation,

$19600000 = 142865.25 + \rho_{gel} \times 9.8 \times 1.35$

$\rho_{gel} = 1470682.89$ $\frac{kg}{m^{3} }$

So specific gravity is given by,

ζ = $\frac{\rho _{gel} }{\rho_{w} }$

ζ = $\frac{1470682.89}{1000}$

ζ = $1470.68$

Therefore, the specific gravity of the gel is 1470.68

5 0

3 years ago

PLEASE HELP THOSE WHO ARE CHEMISTS!! How many molecules are there in 79g of Fe2O3? How many atoms is this?

Shtirlitz [24]

<span><span>1. </span><span>Fe2O3 or Iron (III) oxide is an organic compound. It contains 3 main oxides of Iron, the iron (II) oxide (FeO) and the iron (II, III) oxide (Fe3O4).

Now, let’s find the number of Molecules are there in 79g of Fe203:
The number of Atoms are there:

Molar Mass of Fe2O3 = 160g / mol.
=> 160g of Fe2O<span>3 </span>= 6.02 x 1023 Molecules
=> 79g of Fe2O3 = x
Next, find the value of X, in where:
x = (6.02 x 1023 x 79g) / 160g is approximately
x = 2.97 x 1023 molecules.</span></span>

8 0

3 years ago

50 grams of acetic acid C2H4O2 are dissolved in 200 g of water. Calculate the weight % and mole fraction of the acetic acid in t

Len [333]

$50g$ $of$ $C_2H_4O_2$ $in$ $200g$ $H_2O$

so:

$\frac{50}{200+50}+100\%= \frac{50*100}{250}\%=20\%$

$MW of acid = 2*C+4*H+2*O = 2*12+4*1+2*16=$

$=24+4+32=60g/mol$

so:

$\frac{50g}{60g/mol}\approx0.83moles$

it means that

in $50g$ of acid there is $\approx0.83$ moles of acid

$MW of H_2O = 2*H+O=2*1+16=2+16=18g/mol$

so:

$\frac{200g}{18g/mol}\approx11.11moles$

it means that:

in $200g$ of water there is $\approx11.11$ moles of water

therefore:

$\frac{0.83mol}{11.11mol+0.83mol}= \frac{0.83mol}{11.94mol}=0.069$

So your answers are:

$20\%$

and the mole fraction is:

$0.069$

6 0

3 years ago