Answer:
28 g
Explanation:
The chemical equation of the reaction is given below:
CaCO₃ (s) ⇒ CaO (s) + O₂ (g)
From the chemical equation, 1 mole of CaCO₃ produces 1 mole of CaO.
So, we find the number of moles,n of CaCO₃ in 50 g from
n = m/M where n = number of moles of CaCO₃, m = mass of CaCO₃ and M = molar mass of CaCO₃ = 40 g/mol + 12 g/mol + 3 × 16 g/mol = 52 g/mol + 48 g/mol = 100 g/mol
So, n = m/M
= 50 g/100 g/mol
= 0.5 mol
Since From the chemical equation, 1 mole of CaCO₃ produces 1 mole of CaO, then 0.5 × 1 mole of CaCO₃ produces 0.5 × 1 mole of CaO, which is 0.5 mole of CaCO₃ produces 0.5 mole of CaO.
So, we have 0.5 mol of CaO.
We find the mass of CaO from
n =m'/M' where n = number of moles of CaO = 0.5, m' = mass of CaO and M' = molar mass of CaO = 40 g/mol + 16 g/mol = 56 g/mol
So, m' = nM'
= 0.5 mol × 56 g/mol
= 28 g
