Answer:
C++ With Examples
— Input-restricted Deque: In input-restricted, deletion can be done from ... getLast: Retrieves the last item in the queue. ... Now, we insert element 3 at the rear.
Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.
The Code Given:
import java.util.Scanner;
public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}
Answer:
i would but im not big brain
Explanation:
Answer:
1) 402.7 grams. This estimate is called the sample mean.
2) (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
Explanation:
sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams
1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.
2) c = 99% = 0.99
α = 1 - 0.99 = 0.01
.
The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).
.
The margin of error (e) = 
The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
