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Tanzania [10]
2 years ago
8

A strong magnetic field surrounds Earth. How does Earth’s magnetic field help humans?

Physics
1 answer:
elena-14-01-66 [18.8K]2 years ago
5 0

A strong magnetic field surrounds Earth and (C) It keeps the solar wind from reaching Earth. If all the particles of the solar wind contact the earth, they would make the ozone layer disappear. The ozone layer is the one in charge of protecting the earth from the ultraviolet radiation.

Explanation:

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8. do the earth and the moon always cast shadows? what do we call the occurrence where the earth passes within the shadow of the
Oduvanchick [21]

Yes, they both cast shadows. A  eclipse occurs when one enters the shadow of the other.

Solar eclipse: Earth in shadow of Moon.

Lunar eclipse: Moon in shadow of Earth.

A solar eclipse is the result of one celestial body being completely or partially obscured by another celestial body along the line of sight of an observer. A solar eclipse occurs when the moon passes between the earth and the sun, obscuring all or part of the sun's disk. A lunar eclipse occurs when the Moon passes through the Earth's shadow, making the Moon's surface completely or partially obscured.

Learn more about solar:

https://brainly.in/question/5629706

#SPJ4

8 0
2 years ago
If a body of mass 2 kg is moving with a velocity of 30 m/s, then on doubling its velocity the momentum becomes______.
igor_vitrenko [27]
I think it’s B. So 120kgm/s
8 0
3 years ago
An electric motor rotating a workshop grinding wheel at a rate of 1.31 ✕ 102 rev/min is switched off. Assume the wheel has a con
antoniya [11.8K]

(a) 4.03 s

The initial angular velocity of the wheel is

\omega_i = 1.31 \cdot 10^2 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=13.7 rad/s

The angular acceleration of the wheel is

\alpha = -3.40 rad/s^2

negative since it is a deceleration.

The angular acceleration can be also written as

\alpha = \frac{\omega_f - \omega_i}{t}

where

\omega_f = 0 is the final angular velocity (the wheel comes to a stop)

t is the time it takes for the wheel to stop

Solving for t, we find

t=\frac{\omega_f - \omega_i }{\alpha}=\frac{0-13.7 rad/s}{-3.40 rad/s^2}=4.03 s

(b) 27.6 rad

The angular displacement of the wheel in angular accelerated motion is given by

\theta= \omega_i t + \frac{1}{2}\alpha t^2

where we have

\omega_i=13.7 rad/s is the initial angular velocity

\alpha = -3.40 rad/s^2 is the angular acceleration

t = 4.03 s is the total time of the motion

Substituting numbers, we find

\theta= (13.7 rad/s)(4.03 s) + \frac{1}{2}(-3.40 rad/s^2)(4.03 s)^2=27.6 rad

6 0
3 years ago
A basketball player jumps straight up with a speed of 14 m/s. How high did the player jump?
Gwar [14]

Answer:

ttrftyrdy

Explanation:

tytrterte

3 0
3 years ago
A 6 kg mass collides with a body at rest .After collision they travel together with a velocity equal
Mars2501 [29]

Answer:

12 kg

Explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

After the collision, they have the same velocity, so v₁ = v₂ = v:

m₁ u₁ + m₂ u₂ = m₁ v + m₂ v

m₁ u₁ + m₂ u₂ = (m₁ + m₂) v

We know that m₁ = 6 kg, u₂ = 0 m/s, and v = u₁ / 3.

(6 kg) u₁ + m₂ (0 m/s) = (6 kg + m₂) (u₁ / 3)

(6 kg) u₁ = (6 kg + m₂) (u₁ / 3)

6 kg = (6 kg + m₂) (1/3)

18 kg = 6 kg + m₂

m₂ = 12 kg

3 0
4 years ago
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