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zalisa [80]
1 year ago
6

8. do the earth and the moon always cast shadows? what do we call the occurrence where the earth passes within the shadow of the

moon? when the moon passes within the shadow of the earth?
Physics
1 answer:
Oduvanchick [21]1 year ago
8 0

Yes, they both cast shadows. A  eclipse occurs when one enters the shadow of the other.

Solar eclipse: Earth in shadow of Moon.

Lunar eclipse: Moon in shadow of Earth.

A solar eclipse is the result of one celestial body being completely or partially obscured by another celestial body along the line of sight of an observer. A solar eclipse occurs when the moon passes between the earth and the sun, obscuring all or part of the sun's disk. A lunar eclipse occurs when the Moon passes through the Earth's shadow, making the Moon's surface completely or partially obscured.

Learn more about solar:

https://brainly.in/question/5629706

#SPJ4

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A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate
Olegator [25]

Answer:

See the answers below.

Explanation:

In order to solve this problem we must use the principle of energy conservation. Which tells us that the energy of a body will always be the same regardless of where it is located. For this case we have two points, point A and point B. Point A is located at the top at 120 [m] and point B is in the middle of the cliff at 60 [m].

E_{A}=E_{B}

The important thing about this problem is to identify the types of energy at each point. Let's take the reference level of potential energy at a height of zero meters. That is, at this point the potential energy is zero.

So at point A we have potential energy and since a velocity of 18 [m/s] is printed, we additionally have kinetic energy.

E_{A}=E_{pot}+E_{kin}\\E_{A}=m*g*h+\frac{1}{2}*m*v^{2}

At Point B the rock is still moving downward, therefore we have kinetic energy and since it is 60 [m] with respect to the reference level we have potential energy.

E_{B}=m*g*h+\frac{1}{2}*m*v^{2}

Therefore we will have the following equation:

(6.5*9.81*120)+(0.5*6.5*18^{2} )=(6.5*9.81*60)+(0.5*6.5*v_{B}^{2} )\\3.25*v_{B}^{2} =4878.9\\v_{B}=\sqrt{1501.2}\\v_{B}=38.75[m/s]

The kinetic energy can be easily calculated by means of the kinetic energy equation.

KE_{B}=\frac{1}{2} *m*v_{B}^{2}\\KE_{B}=0.5*6.5*(38.75)^{2}\\KE_{B}=4878.9[J]

In order to calculate the velocity at the bottom of the cliff where the reference level of potential energy (potential energy equal to zero) is located, we must pose the same equation, with the exception that at the new point there is only kinetic energy.

E_{A}=E_{C}\\6.5*9.81*120+(0.5*9.81*18^{2} )=0.5*6.5*v_{C}^{2} \\v_{c}^{2} =\sqrt{2843.39}\\v_{c}=53.32[m/s]

5 0
3 years ago
1. On this graph, what is the change in velocity between 5 seconds and 8 seconds?
alukav5142 [94]
Can I see the graph so I can help you
8 0
2 years ago
A person throws a ball from height of 6 feet with an initial vertical velocity of 48 feet per second. Use the vertical motion mo
True [87]

Explanation:

Recall the equation for time is distance divided by speed. Here you can use that to solve for "t".

7 0
2 years ago
What is the mass of the object if it has a density of 657 g/mL and a volume of 32 mL?<br> Show work!
Luden [163]

Answer:

The answer is 21024g/mL

Explanation:

Multiply 657 by 32:

 657

×  32

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

21024

   ↳            21024 g/mL

3 0
2 years ago
A glass of juice at 20°C was kept in the open. After 30 minutes, the temperature of the Juice remained the same. Which statement
devlian [24]

The answer would be B the temperature of the juice was the temperature of the surrounding air

7 0
3 years ago
Read 2 more answers
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