Answer:
Step-by-step explanation:
On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?
Let:
RM 30 = x
RM 50 = y
x + y = 800 - - - (1)
30x + 50y = 30000 - - - (2)
From (1)
x = 800 - y
Put x = 800 - y in (2)
30(800 - y) + 50y = 30000
24000 - 30y + 50y = 30000
24000 + 20y = 30000
20y = 30000 - 24000
20y = 6000
y =
x=2.7 x 10*-3
Step-by-step explanation:
-815x=2.24
x=-2.24/815
x=2.7 x 10*-3
5x+3y=12
Subtract 5x from both sides
3y=-5x+12
Divide by 3
Y=-5/3x +4
The answer is b. 11.
You can find this by multiplying the two parenthesis together. In order to do this, you can use a multiplying process known as FOIL (First, Outer, Inner, Last), where you multiply parts of the parenthesis in this order to make sure you do so properly.
First Numbers:
2x * x = 2x^2
Outer Numbers:
2x * 6 = 12x
Inner Numbers:
-1 * x = -1x
Last Numbers:
-1*6 = -6
Now place them all in that order and simplify.
2x^2 + 12x - x - 6 ---> simplify x terms
2x^2 + 11x - 6
Since the middle term (the one with the x value) has a coefficient of 11, that gives us a b value of 11.
Multiply 14 to each term: 14a+70+84b
