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2 years ago

The push of energy given to electrons in a circuit is known as what ?

1 answer:

6 0

When a battery is connected to a circuit, the electrons from the anode travel through the circuit toward the cathode in a direct circuit. The voltage of a battery is synonymous with its electromotive force, or emf. This force is responsible for the flow of charge through the circuit, known as the electric current.

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A -0.06 charge that moves downward is in a uniform electric field with a strengthened of 200 N/C. What is the magnitude and dire

Nookie1986 [14]

Answer:

The magnitude of the force is 12 N Upwards

Explanation:

The force on a positive charge will be in the same direction as the field, but the force on a negative charge will be in the opposite direction to the field. Thus the direction of the force is upward.

Given;

magnitude of charge, q = 0.06 C

magnitude of electric field, E = 200 N/C

The magnitude of the force is given by;

F = qE

F = 0.06 x 200 N/C

F = 12 N Upwards

Therefore, the magnitude of the force is 12 N Upwards

5 0

3 years ago

14. The design for a rotating spacecraft below consists of two rings. The outer ring with a radius of 30 m holds the living quar

Zolol [24]

Answer:

$T= 11.0003$ s

Explanation:

From the question we are told that

The outer ring with a radius of 30 m

inner Gravity Approximately 9.80 m/s'

Outer Gravity Approximately 5.35 m/s.

Generally the equation for centripetal force is given mathematically as

Centripetal acceleration enables Rotation therefore?

$\omega ^2 r =Angular\ acc$

Considering the outer ring,

$\omega ^2 r = 9.8$

$\omega ^2= \frac{9.8}{30}$

$\omega = \sqrt{\frac{9.8}{30}}$

$\omega= 0.571 rad/s$

Therefore solving for Period T

Generally the equation for solving Period T is mathematically given as

$T= \frac{2\pi}{\omega}$

$T= \frac{2\pi}{0.571 rad/s}$

$T= 11.0003$ s

5 0

3 years ago

The inductor in a radio receiver carries a current of amplitude 200 mA when a voltage of amplitude 2.4 V is across it at a frequ

zzz [600]

Answer:

The value of the inductance is 1.364 mH.

Explanation:

Given;

amplitude current, I₀ = 200 mA = 0.2 A

amplitude voltage, V₀ = 2.4 V

frequency of the wave, f = 1400 Hz

The inductive reactance is calculated;

$X_l = \frac{V_o}{I_o} \\\\X_l = \frac{2.4}{0.2} \\\\X_l =12 \ ohms$

The inductive reactance is calculated as;

$X_l = \omega L\\\\X_l = 2\pi fL\\\\L = \frac{X_l}{2 \pi f}$

where;

L is the inductance

$L = \frac{12}{2 \pi \times \ 1400} \\\\L = 1.364 \times \ 10^{-3} \ H\\\\L = 1.364 \ mH$

Therefore, the value of the inductance is 1.364 mH.

7 0

3 years ago

The process of thinking that involves considering an overall general idea or theory and drawing specific conclusions or making s

Zigmanuir [339]

<h2>Answer:</h2>

Deductive reasoning

<h2>Explanation:</h2>

The process of using pre-existing knowledge to make logical conclusions, make predictions and draw out explanations is called reasoning. Reasoning are basically of two types:

i. Deductive reasoning: This takes a general rule, idea, or theory as foundation and then proceeds from there to draw meaningful conclusions or predictions. For example;

From above, following from equations (i) and (ii), it can be concluded that (iii) should be true.

ii. Inductive reasoning: While deductive reasoning moves from a general rule to specific rule, inductive reasoning does the opposite - moves from specific to a general rule.

7 0

3 years ago

Calculate the highest frequency X-rays produced by 8.00 · 104 eV electrons. _____ Hz

lys-0071 [83]

When an electron stops, it emits a photon with energy equal to the kinetic energy lost by the electron:
$E=\Delta K$
The energy of the photon is $E=hf$ where $h=6.63 \cdot 10^{-34} Js$ is the Planck constant and f is the frequency. Therefore, the maximum frequency of the emitted photon occurs when the loss of kinetic energy is maximum.

The maximum loss of kinetic energy of the electron occurs when the electron stops completely, so it loses all its energy:
$\Delta K = 8\cdot 10^4 eV$
Keeping in mind that $1 eV=1.6 \cdot 10^{-19}J$ , we have
$\Delta K = 8 \cdot 10^4 eV \cdot 1.6 \cdot 10^{-19}J/eV = 1.28 \cdot 10^{-14}J$

And so, this corresponds to the energy of the emitted photon, E. Therefore, we can find the maximum frequency of the emitted photon:
$f= \frac{E}{h} = \frac{1.28 \cdot 10^{-14}J}{6.63 \cdot 10^{-34}Js}=1.93 \cdot 10^{19}Hz$

5 0

2 years ago