Answer:0.507m
To answer this question, you need to know how to calculate a cube volume. Cube volume is calculated by multiplying the length^3, make its unit become cubic meter.
In this case we know the volume is 130L and asked how long is the length in meter. Then you need to convert the liter into m3. The calculation would be:
V=R^3
130L= R^3
R= 3<span>√(130m3/1000)
R= 5.065797/10 m
R= 0.506579m
Rounded up to 0.507m</span>
Positive - Friction allows us to create heat in a desperate situation, like being lost in the woods. If we didn't have friction, we would probably freeze to death.
Negative - Friction can also cause unwanted fires, such as forest fires. If friction didn't exist, we wouldn't have these.
Answer:B
Explanation:
Given
speed of car 
mass of clump 
Radius of car tire 
Since the tire is rotating about axle so a centripetal force is acting constantly on each particle towards the center of tire.
Centripetal force is given by
where 
(inward)
The final velocity of the ball that is dropped from a height of 200m is v = 44.73 m/s .
<h3>What is velocity with example?</h3>
The rate at which an object is travelling in one direction is referred to as its velocity. an automobile traveling north on a highway, or a rocket taking off. Its velocity vector's absolute value always is equal to the motion's speed because it is a scalar.
<h3>Briefing:</h3>
Given the initial velocity of the ball (u) = 0
Distance travelled by the ball (s) = 200m
Acceleration (a) = 10 m/s²
As we know:
v² = u² + 2as
Putting values:
v² = 0+2 × (10 m/s²) × (200 m)
v = 44.73 m/s.
To know more about Velocity visit:
brainly.com/question/18084516
#SPJ9
Answer:
r = 0.0414mm
F = 757,692.3Hertz
Explanation:
If the body enters space with uniform magnetic field B, the force experienced by the object is expressed as
F = qvBsintheta... 1
Also, if the body undergoes a circular motion, the force experienced by the body in a circular path is given as
Fc = mv²/r... 2
Equating both forces
F = Fc
qvBsin theta = mv²/r
Since the body enters perpendicular to the field, theta = 90°
The equality becomes;
qvB sin90° = mv²/r
qvB = mv²/r
qB = mv/r
r = mv/qB
Given mass of the electron m = 9.11×10^-31kg
Velocity of the object v = 197m/s
Charge on the electron q = 1.6×10^-19C
Magnetic field B = 2.71×10^-5T
Substituting this value into the equation to get the radius r we have;
r = 9.11×10^-31 × 197/1.6×10^-19 × 2.71×10^-5
r = 1794.67×19^-31/4.336×10^-24
r = 413.89×10^-7
r = 0.0000414m
r = 0.0414mm
b) Frequency of the motion F = w/2π where w is the angular velocity
Since w = v/r
F = (v/r)/2π
F = v/2πr
F = 197/2π(0.0000414)
F = 757,692.3Hertz
