I need help factoring an equation.
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Answer:
You can reject the null at the 10% and 5% level of significance, but cannot reject the null at the 2%, or 1% level of significance. ( D )
Step-by-step explanation:
let : P = 0.6
x = 135 , n = 200
<em>p </em>= 135 / 200 = 0.675
H0 : P = 0.6
Ha : P ≠ 0.6
performing the test statistic = ( 0.675 - 0.6 ) /
= 0.075 / 0.0346 ≈ 2.17
p-value = 2 * P ( Z > - 2.17 ) ( using excel function ; NORMSDIST )
= 2 * 0.015 = 0.03