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1 year ago

What is the factored form of 6x2 13x 6? (x 4)(x 9) (2x 3)(3x 2) (2x 6)(3x 1) (6x 1)(6x 1).

Mathematics

1 answer:

mrs_skeptik [129]1 year ago

8 0

Polynomial are expressions. The factored form of the polynomial 6x²+13x+6 is (3x+2)(2x+3).

<h3>What are polynomial?</h3>

Polynomial is an expression that consists of indeterminates(variable) and coefficient, it involves mathematical operations such as addition, subtraction, multiplication, etc, and non-negative integer exponentials.

In order to find the factored form of the given quadratic equation, we will break constant b(13) into two parts such that the sum of the parts is 13, while their product is equal to the product of the constant a(6) and c(6).

$6x2+13x+6\\\\= 6x^2 + 9x + 4x + 6\\\\= 3x(2x+3)+2(2x+3)\\\\=(3x+2)(2x+3)$

Hence, the factored form of the polynomial 6x²+13x+6 is (3x+2)(2x+3).

Learn more about Polynomial:

brainly.com/question/17822016

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Graph for the quadratic formula f(x) = (x - 3) ^2 +5

aksik [14]

Please see the attached graph to see f(x) = (x - 3) ^2 +5 graphed.

6 0

3 years ago

If f(x)= 3x squares +1 and g(x) =1-x what is the value of (f-g)(2)

ZanzabumX [31]

Answer: (f-g)(2)=14

Step-by-step explanation:

(f – g) (-2) means the same as subtracting f(2) and g(2). Since we are given f(x) and g(x), we can use them to solve. There are two ways to solve. One is to find f(2) and g(2), and then subtract them. Another way is to do (f-g)(x), then plug in x=2. I will show both methods.

Method 1

f(2)=3(2)²+1 [exponent]

f(2)=3(4)+1 [multiply]

f(2)=12+1 [add]

f(2)=13

g(2)=1-(2) [subtract]

g(2)=-1

(f-g)(2)=13-(-1) [subtract f(2) and g(2)]

(f-g)(2)=14

--------------------------------------------------------------------------------------------------------

Method 2

(f-g)(x)=3x²+1-(1-x) [distribute -1]

(f-g)(x)=3x²+1-1+x [combine like terms]

(f-g)(x)=3x²+x

(f-g)(2)=3(2)²+2 [plug in x=2, exponent]

(f-g)(2)=3(4)+2 [multiply]

(f-g)(2)=12+2 [add]

(f-g)(2)=14

--------------------------------------------------------------------------------------------------------

Now, we know that (f-g)(2)=14. We confirmed this with both methods.

8 0

3 years ago

A typical sugar cube has an edge length of 1.00 cm. Imagine you have a cubical box that contains a mole of sugar cubes, perfectl

alisha [4.7K]

Answer:

844368.7 m

Step-by-step explanation:

We are given that a typical sugar cube has an edge length of 1.00 cm.

We have to find the edge length of the box in meters.

Edge length of sugar cube=1 cm = $10^{-2}m$ ( $1 cm=\frac{1}{100}m$ )

Volume of a sugar cube= $side\times side\time side=(10^{-2})^3=10^{-6}m^3$

1 mole of sugar= $6.02\times 10^{23}units$

Volume of 1 unit= $10^{-6} m^3$

Volume of $6.02\times 10^{23}$ units= $6.02\times10^{23}\times 10^{-6}=6.02\times 10^{17} m^3$

Volume of box=1 mole of sugar= $6.02\times 10^{17} m^3$

Edge length of box= $\sqrt[3]{6.02\times 10^{17}}=844368.7 m$

6 0

2 years ago

Please help me this is urgent.!

nata0808 [166]

V= 3.14• 5^2•4
V= 3.14 •25•4
V= 78.5•4
V=314

Sorry I couldn’t give a more detailed explanation but here is the original equation for volume of a cylinder:

V=πr2h

Hope this helps comment below for more questions :)

3 0

2 years ago

Read 2 more answers

Jon caught four fish that weighed a total of 252 pounds.The kingfish weighed twice as much as the amberjack and the white marlin

fenix001 [56]

1 Amberjack
Kingfish equals 2 Amberjacks
Marlin equals 2 Kingfish or 4 Amberjacks
Tarpon equals 5 AmberJacks

So:
1A plus 2A plus 4A plus 5A equals the 252.
(where A is weight of the AmberJack).

Therefore:
12A equals 252, and A is 21. (252/12 = 21)

Then:
The Amberjack is 21Ibs.
The Kingfish (twice as much as A) is 42Ibs.
The Marlin (four times A) is 84Ibs.
And the Tarpon (five times A) is 105Ibs.

To Check:
21 + 42 + 84 + 105 = 252

8 0

3 years ago

Read 2 more answers