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musickatia [10]
3 years ago
13

Ayako spent $7.80 on equal weights of beads of white and red beads. The red beads cost twice as much per punce as the white bead

s. How much did Ayako spend on each colour of beads?
Mathematics
2 answers:
Over [174]3 years ago
8 0

$2.60 on white beads and $5.20 on red beads

DENIUS [597]3 years ago
7 0
Ok so
red+white=7.8
r+w=7.8

red=2 times cost of white
r=2w
therefor subsitute 2w for r
2w+w=7.8
3w=7.8
divid both isdes by 3
w=2.6
subsitute
r=2w
r=2(2.6)
r=5.2


$2.60 for white
$5.20 for red

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Answer:

THIS IS HARD

Step-by-step explanation:

8 0
3 years ago
The area of South America is approximately 1.78 × 107 square kilometers. Its population is approximately 3.50 × 108 people. What
stepladder [879]

Answer:

<u>A) 19.66 people/km²</u>

Step-by-step explanation:

<u>Given</u>

  • Area of the continent = 1.78 x 10⁷ km²
  • Population = 3.5 x 10⁸ people

<u>To Find</u>

  • Population Density

<u>Solving</u>

  • population density is the number of people per unit area
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6 0
2 years ago
Write a quadratic equation with a integer coefficients with roots x= 1/2 and x=-4
Misha Larkins [42]

The quadratic equation with roots a and b is given by:

x^2-(a+b)x+ab=0

Here a=1/2 and b=-4.

So the equation is given by:

\begin{gathered} x^2-(\frac{1}{2}-4)x+(\frac{1}{2})(-4)=0 \\ x^2+\frac{7}{2}x-2=0 \\ 2x^2+7x-4=0 \end{gathered}

The quadratic equation is as shown above.

8 0
1 year ago
Can someone help me please
Lady_Fox [76]

i think it is four..?



4 0
3 years ago
Read 2 more answers
An amount of $23,000 is borrowed for 11 years at 6.75% interest, compounded annually. If the loan is paid in full at the end of
Pavel [41]

Answer:

Given that,

An amount of $23,000 is borrowed for 11 years at 6.75% interest, compounded annually.

To find the Amount paid back after 11 years.

Explanation:

we know that,

The formula to find the,

Amount after n years of interest rate r% compounded annually is,

A=P(1+\frac{r}{100})^n

where P is the initial amount.

Here, we have that,

P=$23,000

r=6.75

n=11

Substitute the values we get,

A=23000(1+\frac{6.75}{100})^{11}

Solving this we get,

A=23000(1+0.0675)^{11}A=23000(1.0675)^{11}A=23000(2.05138)A=47181.805

Round to the nearest dollar.

A=47181.805\approx47182

Answer is: Amount paid back is $47182 after 11 years

7 0
1 year ago
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