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2 years ago

Match the description of each sphere to its correct volume.

Mathematics

1 answer:

Crank2 years ago

4 0

Answer:

2085/ 338/32)(80)=32 you have to me 388 to the middle then you add 2085 also the 80 and 32 =32

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Please answer soon. Include Statement and Reason if possible.

Zigmanuir [339]

<h3>Answer: AC = sqrt(21)/2</h3>

====================================================

Explanation:

Triangle CDA is congruent to triangle CDB. We can use the HL (hypotenuse leg) congruence theorem to prove this. This only works because we have two right triangles.

Since CDA and CDB are congruent, this means their corresponding pieces are the same length. Specifically AD = DB, so

AD+DB = AB

AD+AD = 3

2*AD = 3

AD = 3/2 = 1.5

For triangle CDA, we have AD = 3/2 = 1.5 and CD = sqrt(3). We can use the pythagorean theorem to find the missing side AC

a^2 + b^2 = c^2

(AD)^2 + (CD)^2 = (AC)^2

(3/2)^2 + (sqrt(3))^2 = (AC)^2

9/4 + 3 = (AC)^2

(AC)^2 = 9/4 + 3

(AC)^2 = 9/4 + 12/4

(AC)^2 = 21/4

AC = sqrt(21/4)

AC = sqrt(21)/sqrt(4)

AC = sqrt(21)/2

This is the same as writing (1/2)*sqrt(21) or 0.5*sqrt(21)

5 0

4 years ago

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost

Tju [1.3M]

The advance tickets were 35 in number and the same day ticket will be 30 in number.

<h3>What will be the number of tickets?</h3>

To find out the number of the tickets sold we will give some notations so the notations are as follows:-

A= Cost of advance tickets=$30

S= cost of same-day ticket-=15

$N_A=$ Number of the advance tickets

$N_S=$ Number of same-day tickets.

The equations made by the given data will be:-

$30N_A+15N_S=1500\\\\\\N_A+N_S=65$

By solving the above equations:-

$N_S=30\ \ \ \ \ \ N_A=35$

Hence the advance tickets were 35 in number and the same day ticket will be 30 in number.

To know more about linear equations follow

brainly.com/question/14323743

#SPJ1

7 0

3 years ago

Find two numbers such that their difference and also the difference of their cubes are given numbers; say, their difference is 6

ANTONII [103]

Answer:

Step-by-step explanation:

We are to find two numbers such that their difference and also the difference of their cubes are given numbers

Let the two numbers be x+3 and x-3

so that the difference between the numbers is 6.

Difference between the cubes

= $(x+3)^3-(x-3)^3\\= (x+3-x+3)[(x+3)^2+(x-3)^2-(x+3)(x-3)] = 504\\3x^2+9=84\\x^2 = 25\\x = 5 or -5$

So the numbers are either 2 and 8 or

(-2 and -8)

4 0

3 years ago

Lamonte has 80 cents, Maggie has 3/4 of a dollar Gus is has two dimes and a nickle, and beau has six six dimes. Who has the most

Ulleksa [173]

beau has the most money

hope this helps

6 0

3 years ago

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Radda [10]

Answer:

no te entiendo, puedes escribir la pregunta completa

8 0

3 years ago