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Norma-Jean [14]
3 years ago
12

How many moles in 28 grams of UO2?

Chemistry
2 answers:
Leya [2.2K]3 years ago
8 0

Answer:

There are 0.135moles of UO2 in 28 grams of UO2

Explanation:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 mole UO2, or 207.03grams.

This is the molar mass of UO2, calculated from the sum of the molar masses of uranium and oxygen.

That is, molar mass of UO2= molar mass of U + (molar mass of O)2

=238.03g/mol + (16g/mol)2

= 238.03g/mol + 32g/mol= 270.03g/mol

Molar mass of UO2= 270.03g/mol

This implies that 1 mole of UO2 has a mass of 207.03 grams

Number of moles of UO2 = mass of UO2/ molar mass of UO2

Mass of UO2= 28 grams

Number of moles of UO2= 28 g/ 207.03gmol-1

Number of moles =0.1352 moles of UO2

Therefore, there are 0.135 moles of UO2 in 28 grams of UO2.

Lina20 [59]3 years ago
3 0
0.22 moles.

28 divided by 124 =0.22
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Answer:

In order for the powder to dissolve, each powder molecule must separate from the other powder molecules and be surrounded by water molecules. This shift in arrangement either absorbs or releases energy depending on the situation. It is due to the exchange of energy that the temperature of the solution fluctuates.

Explanation:

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5 0
3 years ago
In the reaction below, how many grams of h2o(g) are produced when 2.1 grams o2(g) are consumed? c4h6(g) + o2(g) → co2(g) + h2o(g
amm1812
The balanced equation that illustrates the reaction is:
2C4H6 + 11O2 ......> 8CO2 + 6H2O 

number of moles = mass / molar mass 
number of moles of oxygen = 2.1 / 32 = 0.065625 moles

Now, from the balanced equation, we can note that:
11 moles of oxygen are required to produce 6 moles of water.
Therefore:
0.065625 moles of oxygen will produce:
(0.065625*6) / 11 = 0.03579 moles of water

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3 0
3 years ago
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The rate at which an electrical device converts energy from one form to another is called what
zlopas [31]
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3 years ago
What is the mass in grams of 5.00moles of CH4?
anastassius [24]

Answer:

1. 80g

2. 1.188mole

Explanation:

1. We'll begin by obtaining the molar mass of CH4. This is illustrated below:

Molar Mass of CH4 = 12 + (4x1) = 12 + 4 = 16g/mol

Number of mole of CH4 from the question = 5 moles

Mass of CH4 =?

Mass = number of mole x molar Mass

Mass of CH4 = 5 x 16

Mass of CH4 = 80g

2. Mass of O2 from the question = 38g

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Number of mole O2 =?

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6 0
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The equilibrium constant for the gas phase reaction N2 (g) + O2 (g) ⇌ 2NO (g) is Keq = 4.20 ⋅ 10-31 at 30 °C. At equilibrium, __
pychu [463]

Answer:

At equilibrium, reactants predominate.

Explanation:

For every reaction, the equilibrium constant is defined as the ratio between the concentration of products and reactants. Thus, for the reaction N2 (g) + O2 (g) ⇌ 2NO the expression of its equilibrium constant is:

Keq = \frac{[NO]^{2}}{[O_{2} ][N_{2}]}

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5 0
3 years ago
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