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Norma-Jean [14]
3 years ago
12

How many moles in 28 grams of UO2?

Chemistry
2 answers:
Leya [2.2K]3 years ago
8 0

Answer:

There are 0.135moles of UO2 in 28 grams of UO2

Explanation:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 mole UO2, or 207.03grams.

This is the molar mass of UO2, calculated from the sum of the molar masses of uranium and oxygen.

That is, molar mass of UO2= molar mass of U + (molar mass of O)2

=238.03g/mol + (16g/mol)2

= 238.03g/mol + 32g/mol= 270.03g/mol

Molar mass of UO2= 270.03g/mol

This implies that 1 mole of UO2 has a mass of 207.03 grams

Number of moles of UO2 = mass of UO2/ molar mass of UO2

Mass of UO2= 28 grams

Number of moles of UO2= 28 g/ 207.03gmol-1

Number of moles =0.1352 moles of UO2

Therefore, there are 0.135 moles of UO2 in 28 grams of UO2.

Lina20 [59]3 years ago
3 0
0.22 moles.

28 divided by 124 =0.22
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By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling or exhaling then

p_{1} =patm+pH_{2} O

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It is known that volume and pressure can be expressed as:

V*P=const.

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Now,              

V_{1} *p_{1} =V_{2}  *p_{2}

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Assume constant temperature

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V_{1} *p_{1} =V_{2}  *p_{2}

V_{2} /V_{1}=p_{2} /p_{1}

V_{2} /V_{1} =490036.44/X

p_{2} =490036.44pa/(V2/V1) =326690.96Pa

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p_{2} =101325Pa+ρgh_{2}

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h_{2} =225365.96/‬ρ∗g

​h_{2}  =225365.96  / ‬1040∗9.81

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So she can safely ascend up to 52.53 ft without Breathing out

To know more about Scuba diver here

brainly.com/question/15430942

#SPJ4

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