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Sloan [31]
3 years ago
8

Carbon disulfide burns with oxygen to form carbon dioxide and sulfur dioxide in the following manner: CS2 + 3O2 → CO2 + 2SO2

Chemistry
1 answer:
Virty [35]3 years ago
4 0

Answer:

89.6 L.

Explanation:

  • For the balanced reaction:

<em>CS₂ + 3O₂ → CO₂ + 2SO₂.</em>

  • It is clear that <em>1.0 mole of CS₂</em> with 3.0 moles of O₂ to produce 1.0 mole of  CO₂ and <em>2.0 moles of SO₂.</em>

<em></em>

<u><em>Using cross multiplication:</em></u>

1.0 mole of CS₂ produces → 2.0 moles of SO₂.

2.0 mole of CS₂ produces → ??? moles of SO₂.

∴ The no. of moles of SO₂ produced = (2.0 mol)(2.0 mol)/(1.0 mol) = 4.0 mol.

  • It is known that 1.0 mole of any gas at STP occupies 22.4 L.

<em>∴ 4.0 moles of SO₂ occupy = (4.0)(22.4 L) = 89.6 L.</em>

<em></em>

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Answer:

B. The student chose the correct tile, but needs to flip the tile to make the units cancel

Explanation:

Based on the reaction:

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<em>2 moles of AgNO₃ react per mole of Cu producing 2 moles of Ag and 1 mole of Cu(NO₃)₂</em>

Thus, if you want to produce 6.75moles of Cu(NO₃)₂ you need:

6.75moles of Cu(NO_3)_2  \frac{2 mol AgNO_3 }{1 mol Cu(NO_3)_2} = 13.50 moles of AgNO₃ are needed

Thus, if you analize the tile shown by the student:

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3 years ago
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Please help on 44. /45./ 46./47,
Aleonysh [2.5K]
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Foxeslair
4 0
4 years ago
The radioactive decay of a certain sample produced 846 disintegrations per minute. exactly 3.00 days later, the rate of decay wa
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Answer:

\boxed{\text{1.81 da}}

Explanation:

1. Calculate the decay constant

The integrated rate law for radioactive decay is 1

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k is the radioactive decay constant

\ln \dfrac{846}{269} = k \times 3.00\\\\\ln3.145 = 3.00k\\1.146 = 3.00k\\\\k =\dfrac{1.146}{3}\\\\k = \text{0.382 /da}\\

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